A force F= (6.70 N)i + (5.60 N)j + (6.60 N)k act on a 9.80 kg mobile object that moves from an initial position of di = (9.10 m)
i + (5.30 m)j + (6.70 m)k to a final position of df = (8.00 m)i + (9.70 m)j + ( 3.30 m)k in 5.90 s.
Find (a) the work done on the object by the force in the 5.90 s interval, (b) the average power due to the force during that interval.
Find (a) the work done on the object by the force in the 5.90 s interval, (b) the average power due to the force during that interval.
1 answer:
You might be interested in