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Luda [366]
3 years ago
10

pls balance the following chemical equation asap; Ca(OH)2 +CO2 = CaCO3+ H2O​ pls make it step by step

Chemistry
1 answer:
Mrac [35]3 years ago
6 0

Answer:

Explanation:

Start by writing water as HOH

Ca(OH)2 +CO2 = CaCO3+ HOH

Next pay attention to the CO2 going to CO3

We need an oxygen.

Fortunately that is provided by the (OH)2

Now we have

Ca(OH)2 + CO2 ==> CaCO3 + HOH

and believe it or not, that is balanced as it is

The left side has 1 Ca. So does the right side

The Left side has 1 C.  So does the right side.

The left side has 2 H. So does the right side

The left side has 2 oxygens (in Ca(OH2)) + 2 oxygens in CO2

So the equation is balanced.

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ones that can be mixed together

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like water or ethanol

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If thermal energy (heat) must be added to a chemical reaction in order for the reaction to take place, the reaction is _________
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<span>If thermal energy (heat) must be added to a chemical reaction in order for the reaction to take place, the reaction is endothermic. </span>
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If 60. liters of hydrogen gas at 546 K is cooled to 273 K at constant pressure, the new volume of the gas would be
Korvikt [17]

Answer:30 L

Explanation:

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V

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i

t

e

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Final Vloume

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Since the pressure is constant and the question is asking about temperature and volume, i.e,

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30

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=

30

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i

t

e

r

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30

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i

t

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6 0
3 years ago
The most common source of copper (cu) is the mineral chalcopyrite (cufes2). how many kilograms of chalcopyrite must be mined to
tigry1 [53]

Answer : 0.8663 Kg of chalcopyrite must be mined to obtained 300 g of pure Cu.

Solution : Given,

Mass of Cu = 300 g

Molar mass of Cu = 63.546 g/mole

Molar mass of CuFeS_2 = 183.511 g/mole

  • First we have to calculate the moles of Cu.

\text{ Moles of Cu}=\frac{\text{ Given mass of Cu}}{\text{ Molar mass of Cu}}= \frac{300g}{63.546g/mole}=4.7209moles

The moles of Cu = 4.7209 moles

From the given chemical formula, CuFeS_2 we conclude that the each mole of compound contain one mole of Cu.

So, The moles of Cu = Moles of CuFeS_2 = 4.4209 moles

  • Now we have to calculate the mass of CuFeS_2.

Mass of CuFeS_2 = Moles of CuFeS_2 × Molar mass of CuFeS_2 = 4.4209 moles × 183.511 g/mole = 866.337 g

Mass of CuFeS_2 = 866.337 g = 0.8663 Kg         (1 Kg = 1000 g)

Therefore, 0.8663 Kg of chalcopyrite must be mined to obtained 300 g of pure Cu.


3 0
3 years ago
When HClO2 is dissolved in water, it partially dissociates according to the equation
Natasha_Volkova [10]

Answer:

x = 100 * 1.1897 = 118.97 %, which is > 100 meaning that all of the HClO2 dissociates

Explanation:

Recall that , depression present in freezing point is calculated with the formulae = solute particles Molarity x KF

0.3473 = m * 1.86

Solving, m = 0.187 m

Moles of HClO2 = mass / molar mass = 5.85 / 68.5 = 0.0854 mol

Molality = moles / mass of water in kg = 0.0854 / 1 = 0.0854 m

Initial molality

Assuming that a % x of the solute dissociates, we have the ICE table:

                 HClO2         H+    +   ClO2-

initial concentration:       0.0854                    0             0

final concentration:      0.0854(1-x/100)   0.0854x/100   0.0854x / 100

We see that sum of molality of equilibrium mixture = freezing point molality

0.0854( 1 - x/100 + x/100 + x/100) = 0.187

2.1897 = 1 + x / 100

x = 100 * 1.1897 = 118.97 %, which is > 100 meaning that all of the HClO2 dissociates

3 0
3 years ago
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