Vi=0
T=3.07s
D=46m
A=?
A=2(d)/t ^2
2(46)/3.07^2=9.8m/s^2
The following equations show how kinetic energy (KE), potential energy (PE), and total mechanical energy (ME) are solved.
KE = 0.5mv²
PE = mgh
ME = PE + KE
where m is mass, v is speed/velocity, g is gravitational constant, and h is height.
Substituting for number 1,
KE = 0.5(2000 kg)(30 m/s)² 900,000 J
PE = (2000 kg)(9.8 m/s²)(0 m) = 0
ME = 900,000 J
I believe you will be able to answer the rest of the items following the same principles as presented above.
Answer:
8.4 kN
Explanation:
Change in momentum = m₁v₁- m₂v₂ = m(v₁-v₂) = 1.2[8 - (-6)] = 16.8kgm/s
v₂ has been taken as negative because velocity of object colliding ball as +ve. Both are in opposite directions.
Change in momentum = impulse = Force × Time
Time = 2 ms = 2 milli seconds = 0.002 s.
Force = Change in momentum/Time = 16.8/0.002 = 8.4kN
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