Question

An elevator is raised by a cable, as shown in the diagram. If the mass of the elevator is 715 kg and the tension in the

Answer 1

First find the weight of the elevator by doing mass*gravity. It’s 7007 N. So now find the net force on the system by adding the vertical components of the force. We have a positive 8000 N from the tension plus a negative 7007 N from the weight of the elevator.

Net force:
8000 N - 7007 N = 993 N
Now do 993 N = ma
993 N / 715 kg = 1.39 m/s^2

Answer 2

Answer:

1.379 m/s2

Explanation:

F=ma

There is a negative force from the elevator...

F = (715 kg) (-9.81 m/s2)

F = -7014.15 N

Cable + elevator = 8000 N + (-7014.15 N)

F = 985.85 N

a = F/m

985.85 N/715 kg = 1.379 m/s2