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SVEN [57.7K]
3 years ago
11

An elevator is raised by a cable, as shown in the diagram. If the mass of the elevator is 715 kg and the tension in the

Physics
2 answers:
ELEN [110]3 years ago
4 0
First find the weight of the elevator by doing mass*gravity. It’s 7007 N. So now find the net force on the system by adding the vertical components of the force. We have a positive 8000 N from the tension plus a negative 7007 N from the weight of the elevator.

Net force:
8000 N - 7007 N = 993 N
Now do 993 N = ma
993 N / 715 kg = 1.39 m/s^2
Lisa [10]3 years ago
3 0

Answer:

1.379 m/s2

Explanation:

F=ma

There is a negative force from the elevator...

F = (715 kg) (-9.81 m/s2)

F = -7014.15 N

Cable + elevator = 8000 N + (-7014.15 N)

F = 985.85 N

a = F/m

985.85 N/715 kg = 1.379 m/s2

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When the cylinder is displaced slightly along its vertical axis it will oscillate about its equilibrium position with a frequenc
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now let's use the concept of density to calculate the mass of the system

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let's substitute

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        w² = g L / (½ r² + 2/3 L²)

        L >> r

         w = √[g /L (½ r²/L2 + 2/3 ) ]

When the mass of the cylinder changes if its external dimensions do not change the angular velocity DOES NOT CHANGE

4 0
3 years ago
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