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3 years ago

PLEASE ANSWER FAST!!! WILL GIVE BRAINLIEST!!!!!

Physics

2 answers:

Alex17521 [72]3 years ago

5 0

I would go with Segment D.

Natali5045456 [20]3 years ago

5 0

Straight segment D. (Choice-D)

As time goes on, the position is decreasing at a constant rate.

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How does the suns energy contribute to the carbon cycle

ozzi

Answer:

Photosynthesis

Light energy from the sun stimulates photosynthesis by green plants. One major component of the carbon cycle is the reduction of the carbon (IV) oxide content in the atmosphere by plants. Plants take in Carbon (IV) oxide to use during the process of making their own food. During this process light energy is absorbed by chlorophyll and is used to convert carbon (IV) oxide and water to glucose.

This glucose is used during respiration by living organisms that give out carbon (IV) oxide. The cycle continues.

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3 years ago

A rifle with a weight of 25 N fires a 4.5-g bullet with a speed of 240 m/s. (a) Find the recoil speed of the rifle. m/s (b) If a

asambeis [7]

Answer:

The recoil speed of the man and rifle is $v_{man}=0.016 ms^{-1}$ .

Explanation:

The expression for the force in terms of mg is as follows;

F=mg

Here, m is the mass and acceleration due to gravity.

Rearrange the expression for mass.

$m=\frac{F}{g}$

Calculate the combined mass of the man and rifle.

$m_{man,rifle}=\frac{650+25}{g}$

Put $g=9.8 ms^{-2}$ .

$m_{man,rifle}=\frac{650+25}{9.8}$

$m_{man,rifle}=68.88 kg$

The expression for the conservation of momentum is as follows as;

$m_{man}u_{man}+m_{bullet}u_{bullet}=m_{man}v_{man}+m_{rifle}v_{man,rifle}$

Here, $m_{man,rifle}$ is the mass of the man and rifle, $m_{rifle}$ is the mass of the rifle, $u_{man},u{bullet}$ are the initial velocities of the man and bullet and $v_{man},v{man,rifle}$ are the final velocities of the man and rifle and rifle.

It is given in the problem that a rifle with a weight of 25 N fires a 4.5-g bullet with a speed of 240 m/s.

Convert mass of rifle from gram to kilogram.

$m_{bullet}=4.5 g$

$m_{bullet}=.0045 kg$

Put $m_{bullet}=.0045 kg$ , $m_{man,rifle}=68.88 kg$ , $u_{man,rifle}=0$ , $v_{bullet}= 240 ms^{-1}$ and $u_{bullet}=0$ .

$m_{man}(0)+m_{bullet}(0)=(68.88)v_{man,rifle}+(.0045)(240)$

$0=(68.88)v_{man,rifle}+(.0045)(240)$

$0=(68.88)v_{man,rifle}+1.08$

$(68.88)v_{man,rifle}=\frac{-1.08}{68.88}$

$v_{man,rifle}=-0.016 ms^{-1}$

Therefore, the recoil speed of the man and rifle is $v_{man}=0.016 ms^{-1}$ .

3 0

3 years ago

The wavelength of a light wave will affect the light’s

Degger [83]

The answer is a because
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3 years ago

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Whenever an object is moving at a constant rate, the value(s) that equal zero is (are):

dolphi86 [110]

Answer:

d) all of the above

Explanation:

the speed, velocity, and acceleration all changes to 0 due to no motion.

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3 years ago

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