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Nookie1986 [14]
3 years ago
10

If an atom has 18 protons,17 neutrons,and 19 electrons what is the atom electrical charge?

Chemistry
2 answers:
Leviafan [203]3 years ago
8 0

Answer: D: -1

Explanation: All protons have a +1 charge, neutrons are neutral, and electron have a -1 charge. Therefore it can be concluded that if the atom has 18 protons which all have +1 charge and 19 electrons which all have -1 charge, then the atom will have a -1 charge since 18-19=-1

Natasha_Volkova [10]3 years ago
4 0

Answer:

D: -1

Explanation:

18 protons so +18

19 electrons -19

neutrons dont count there neutral

-19+18= -1

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In 1782 a French chemist named ________ proposed a systematic nomenclature for naming chemical compounds.
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Explanation:

He is who proposed the first systematic nomenclature for naming chemical compounds.

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Solve the ideal gas law equation for pressure.
posledela

Answer:

p=\frac{nRT}{V}

Explanation:

The ideal gas law equation is an equation that relates some of the quantities that describe a gas: pressure, volume and temperature.

The equation is:

pV=nRT

where

p is the pressure of the gas

V is the volume of the gas

n is the number of moles of the gas

R is the gas constant

T is the absolute temperature of the gas (must be expressed in Kelvin)

Here we want to solve the equation isolating p, the pressure of the gas.

We can do that simply by dividing both terms by the volume, V. We find:

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6 0
3 years ago
Calculate the percent ionization of nitrous acid in a solution that is 0.249 M in nitrous acid. The acid dissociation constant o
sattari [20]

Answer:

4.26 %

Explanation:

There is some info missing. I think this is the original question.

<em>Calculate the percent ionization of nitrous acid in a solution that is 0.249 M in nitrous acid. The acid dissociation constant of nitrous acid is  4.50  ×  10 ⁻⁴.</em>

<em />

Step 1: Given data

Initial concentration of the acid (Ca): 0.249 M

Acid dissociation constant (Ka): 4.50  ×  10 ⁻⁴

Step 2: Write the ionization reaction for nitrous acid

HNO₂(aq) ⇒ H⁺(aq) + NO₂⁻(aq)

Step 3: Calculate the concentration of nitrite in the equilibrium ([A⁻])

We will use the following expression.

[A^{-} ] = \sqrt{Ca \times Ka } = \sqrt{0.249 \times 4.50 \times 10^{-4}  } = 0.0106 M

Step 4: Calculate the percent ionization of nitrous acid

We will use the following expression.

\alpha = \frac{[A^{-} ]}{[HA]} \times 100\% = \frac{0.0106M}{0.249} \times 100\% = 4.26\%

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