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3 years ago

Give an example of a model code.

Engineering

1 answer:

Zanzabum3 years ago

6 0

Answer:

Model codes are the codes which used to change the location of a machine from one place to other place to perform specific task.g and M are the model codes which used in machines.

Ex:

G0 ,G1 , G2 ,G80 ,G81 ... For motion

G17 ,G18 , G19 For planer selection

Mo ,M1 , M2 ,M30 ,M60 For Stopping

M6 For tool change

M26 ,27 For clamping

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If the bending moment (M) is 4,176 ft-lb and the beam is an 1 beam, calculate the bending stress (psi) developed at a point with

SpyIntel [72]

Answer:

Bending stress at point 3.96 is \sigma_b = 1.37 psi

Explanation:

Given data:

Bending Moment M is 4.176 ft-lb = 50.12 in- lb

moment of inertia I = 144 inc^4

y = 3.96 in

$\sigma_b = \frac{M}{I} \times y$

putting all value to get bending stress

$\sigma_b = \frac{50.112}{144} \times 3.96$

$\sigma_b = 1.37 psi$

Bending stress at point 3.96 is $\sigma_b$ = 1.37 psi

3 0

3 years ago

Suppose that you can throw a projectile at a large enough v0 so that it can hit a target a distance R downrange. Given that you

viktelen [127]

Answer:

$\theta_1=15^o\\\theta_2=75^o$

Explanation:

<u>Projectile Motion</u>

In projectile motion, there are two separate components of the acceleration, velocity and displacement. The horizontal component has zero acceleration (assuming no friction), and the acceleration in the vertical direction is always the acceleration of gravity. The basic formulas are shown below:

$V_x=V_{ox}=V_ocos\theta$

Where $\theta$ is the angle of launch respect to the positive horizontal direction and Vo is the initial speed.

$V_y=V_{oy}-gt=V_osin\theta-gt$

The horizontal and vertical distances are, respectively:

$x=V_{o}cos\theta t$

$\displaystyle y=y_o+V_{o}sin\theta t-\frac{gt^2}{2}$

The total flight time can be found as that when y = 0, i.e. when the object comes back to ground (or launch) level. From the above equation we find

$\displaystyle t_f=\frac{2V_osin\theta}{g}$

Using this time in the horizontal distance, we find the Range or maximum horizontal distance:

$\displaystyle R=\frac{V_o^2sin2\theta}{g}$

Let's solve for $\theta$

$\displaystyle sin2\theta=\frac{R.g}{V_o^2}$

This is the general expression to determine the angles at which the projectile can be launched to hit the target. Recall the angle can have to values for fixed positive values of its sine:

$\displaystyle \theta_1=\frac{asin\left(\frac{R.g}{V_o^2}\right)}{2}$

$\displaystyle \theta_2=\frac{180^o-asin\left(\frac{R.g}{V_o^2}\right)}{2}$

Or equivalently:

$\theta_2=90^o-\theta_1$

Given Vo=37 m/s and R=70 m

$\displaystyle \theta_1=\frac{asin\left(\frac{70\times 9.8}{37^2}\right)}{2}$

$\theta_1=15^o$

And

$\theta_2=90^o-15^o=75^o$

5 0

3 years ago

The oil system is:

kirill [66]

Answer:

From the main bearings, the oil passes through feed-holes into drilled passages in the crankshaft and on to the big-end bearings of the connecting rod.

3 0

2 years ago

Sum of Numbers Design a function that accepts an integer argument and returns the sum of all the integers from 1 up to the numbe

cestrela7 [59]

Answer:

# define main to get an argument from the user, call the function, and display the final values

def main():

# ask an argument from the user.

number = int(input('Enter a positive integer: '))

# solve the integral thing of the number by putting the user's argument in the addition() function

finalSum = addition(number)

# display the final value integral thing

print("The integral of this number is ", finalSum, ".")

# define an addition function to find the integral

def addition(num):

# make an if-statement to test filter things out of your calculations. In this case, 1.

if num == 1:

#if 1, return 1. because 1 + (1 - 1) = 1

return 1

# this is where the recursion actually is. This is the part that calculates

else:

return num + addition(num-1)

# call your main function

main()

Explanation:

This is written in Python. A link to the output can be found below.

https://Sum-of-Numbers.hufflepuffler07.repl.run

4 0

3 years ago

You buy a 75-W lightbulb in Europe, where electricity is delivered to homes at 240V. If you use the lightbulb in the United Stat

givi [52]

Answer:

The bulb will be $\frac{1}{4}$ times as bright as it is in Europe.

Explanation:

Data provided in the question:

Power of bulb in Europe = 75 W

Voltage provided in Europe = 240 V

Voltage provided in United Stated = 120 V

Now,

We know,

Power = Voltage² ÷ Resistance

Therefore,

75 = 240² ÷ Resistance

Resistance = 240² ÷ 75

Resistance = 768 Ω

Therefore,

Power in United States = Voltage² ÷ Resistance

= 120² ÷ 768

= 18.75 W

Therefore,

Ratio of powers

$\frac{\text{Power in united states}}{\text{Power in Europe}}=\frac{18.75}{75}$

= $\frac{1}{4}$

Hence,

The bulb will be $\frac{1}{4}$ times as bright as it is in Europe.

7 0

2 years ago