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sergiy2304 [10]
3 years ago
6

If the bending moment (M) is 4,176 ft-lb and the beam is an 1 beam, calculate the bending stress (psi) developed at a point with

a distance of c = 3.96 in from its centroid. The moment of inertia is 144 in^4.
Engineering
1 answer:
SpyIntel [72]3 years ago
3 0

Answer:

Bending stress at point 3.96 is \sigma_b = 1.37 psi

Explanation:

Given data:

Bending Moment M is 4.176 ft-lb = 50.12 in- lb

moment of inertia I = 144 inc^4

y = 3.96 in

\sigma_b = \frac{M}{I} \times y

putting all value to get bending stress

\sigma_b = \frac{50.112}{144} \times 3.96  

\sigma_b =  1.37 psi

Bending stress at point 3.96 is \sigma_b = 1.37 psi

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Xelga [282]

Answer:

a) aA = - 13.33 mm/s²

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c) vB = 70 mm/s

d) xB = 440 mm

Explanation:

Given

The initial speed of B is: v₀B = 150 mm/s

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Assuming:

Displacement of blocks are denoted by:

A = xA

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From the pic shown, the total length of the cable is:

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where L - 2*d is constant. Differentiating the above equation with respect to time:

d(2*xB)/dt - d(3*xA)/dt = 0

⇒ 2*vB - 3*vA = 0    (i)

Substituting in equation (i)

2*(150 mm/s) - 3*vA = 0

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Then, we use the equation

vA² = v₀A² + 2*aA*xA

Substituting the values in above equation:

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Differentiating the above equation with respect to time:

d(2*vB)/dt - d(3*vA)/dt = 0

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Substituting in equation (ii)

2*aB - 3*(- 13.33 mm/s²) = 0

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b) From the pic shown,

xD - xA = constant

If we apply

d(xD)/dt - d(xA)/dt = 0

⇒ vD - vA = 0

then

d(vD)/dt - d(vA)/dt = 0

⇒ aD - aA = 0

⇒ aD = aA = - 13.33 mm/s²

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vB = v₀B + aB*t

Substituting the values in above equation:

vB = 150 mm/s + (- 20 mm/s²)*(4 s)

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xB = v₀B*t + 0.5*aB*t²

Substituting the values in above equation:

xB = (150 mm/s)*(4 s) + 0.5*(- 20 mm/s²)*(4 s)²

⇒ xB = 440 mm

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Now if you plug in Tan(z) and simplify (it is easy!) you get

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This means that

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Now,

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Answer:

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sergejj [24]

Answer:

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Three methods are given to heat a particular house are as follows:

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Method (b)

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Method (c)

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Step2

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