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ser-zykov [4K]
3 years ago
14

At a specified point on a highway, vehicles are known to arrive according to a Poisson process. Vehicles are counted in 20-secon

d intervals, and vehicle counts are taken in 120 of these time intervals. It is noted that no cars arrive in 18 of these 120 intervals. Approximate the number of these 120 intervals in which exactly three cars arrive.
Engineering
1 answer:
torisob [31]3 years ago
4 0

Answer:

Explanation:

  • Given vehicles are counted = 20secs
  • vehicles counted are taken in = 120 time intervals
  • no cars arrive in 18 of these 120 intervals

  • from poisson distribution P(x) = e^-λ λ^x /x!
  • P(0) = 18/120 = e^-λ
  • λ = 0.1897

Similarly, for P(3) = e^-0.1897 X 1.897^3 /3!

= 0.1707

  • Therefore, Number of intervals in which exactly three cars arrive.
  • = 120P(3) = 120(0.1707)
  • = 20.47 , Approximately 21 is the number of intervals

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nydimaria [60]

<em>Answer:</em>

<h3><em>1. Check mirrors</em></h3><h3><em>2. Put on your seat belt</em></h3>

<em>Explanation:</em>

<em>1. Checking your mirrors are very important because if someone screwed with them then it can mess up your driving. </em>

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7 0
3 years ago
Two loads connected in parallel draw a total of 2.4 kW at 0.8 pf lagging from a 120-V rms, 60-Hz line. One load absorbs 1.5 kW a
stealth61 [152]

Answer: a) 0.948 b) 117.5µf

Explanation:

Given the load, a total of 2.4kw and 0.8pf

V= 120V, 60 Hz

P= 2.4 kw, cos θ= 80

P= S sin θ - (p/cos θ) sin θ

= P tan θ(cos^-1 (0.8)

=2.4 tan(36.87)= 1.8KVAR

S= 2.4 + j1. 8KVA

1 load absorbs 1.5 kW at 0.707 pf lagging

P= 1.5 kW, cos θ= 0.707 and θ=45 degree

Q= Ptan θ= tan 45°

Q=P=1.5kw

S1= 1.5 +1.5j KVA

S1 + S2= S

2.4+j1.8= 1.5+1.5j + S2

S2= 0.9 + 0.3j KVA

S2= 0.949= 18.43 °

Pf= cos(18.43°) = 0.948

b.) pf to 0.9, a capacitor is needed.

Pf = 0.9

Cos θ= 0.9

θ= 25.84 °

(WC) V^2= P (tan θ1 - tan θ2)

C= 2400 ( tan (36. 87°) - tan (25.84°)) /2 πf × 120^2

f=60, π=22/7

C= 117.5µf

7 0
3 years ago
A certain piece of property is assessed at $150,000. If the tax rate is $2.50 per $100, what is the tax on this property?
stiks02 [169]

Answer:

The tax on this property is 3750 dollars

Explanation:

Given

Tax on per $100 is $2.50

Tax on every $1 is \frac{2.5}{100} = 0.025 dollars

Tax on property of value $150,000 is

150,000 * 0.025 = 3750 dollars

The tax on this property is 3750 dollars

7 0
3 years ago
How would I find the Voltage across the open circuit
Nimfa-mama [501]

Answer:

  Vab = 80V

Explanation:

The only current flowing in the circuit is supplied by the 100 V source. Its only load is the 40+60 ohm series circuit attached, so the current in that loop is (100V)/(40+60Ω) = 1A. That means V1 = (1A)(60Ω) = 60V.

Vab will be the sum of voltages around the right-side "loop" between terminals 'a' and 'b'. It is (working clockwise from terminal 'b') ...

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3 0
2 years ago
How much work, in Newtons, is required to lift a 20.4-kg (45lb) plate from the ground to a stand that is 1.50 meters up?
nataly862011 [7]

Answer:

Explanation:

Work, U, is equal to the force times the distance:

U = F · r

Force needed to lift the weight, is equal to the weight: F = W = m · g

so:

U = m · g · r

   = 20.4kg · 9.81 \frac{N}{kg} · 1.50m

   = 35.316 \frac{N}{m}

   = 35.316 W

4 0
2 years ago
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