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2 answers:
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Answer:
d = 1600 m
Explanation:
If car start from rest and accelerates uniformly then the displacement of the car is given as
now we know
now if the same car will accelerate from rest for four times of the previous time interval
then we will have
so the distance will be 16 times more
Answer:
Proton’s speed, a short time later when it reaches a point of lower potential is 1.4 x 10⁵ m/s
Explanation:
Given;
initial speed of proton, u = 2.5 x 10⁵ m/s
initial potential, V = 1500 V
mass of proton = 1.67 x 10⁻²⁷ kg
Work done, W = eV= ΔK.E = ¹/₂mu²
eV = ¹/₂mu² (J)
where;
e is the charge of the proton in coulombs
V is the electric potential in volts
m is the mass of the proton in kg
u is the speed of the proton in m/s
Therefore, proton’s speed a short time later when it reaches a point of lower potential is 1.4 x 10⁵ m/s