Answer:
a)0.024
b)0.148
Explanation:
Let 's represent the set of deer ticks Carrying Lyme disease with L and the set of deer ticks carrying Human Granulocytic Ehrlichiosis with H
Given:
P(L) = 0.16
P(H) = 0.10
P(L n H) = 0.1 ·P( L u H )
Hence, P( L u H) = 10 ·P( L nH)
(a)
Hence. using the equation. P(L U H) = P(L) + P(H) - P(L n H)
Hence, 10 · P(L n H ) = 0.16 + 0.1 - P(L n H )
Hence, 11 · P(L n H) = 0.16 + 0.1 = 0.26
Hence, P(L n H) =
0.26/11=0.024
(b)
We know that condition probability P(H ║ L) = p(L n H)/P(L)
hence, P(H ║ L) =(0.26/11)/0.16 =0.148
i believe the answer is C.
Answer:
The frictional force acting on the block is 14.8 N.
Explanation:
Given that,
Weight of block = 37 N
Coefficients of static = 0.8
Kinetic friction = 0.4
Tension = 24 N
We need to calculate the maximum friction force
Using formula of friction force
Put the value into the formula
So, the tension must exceeds 29.6 N for the block to move
We need to calculate the frictional force acting on the block
Using formula of frictional force
Put the value in to the formula
Hence, The frictional force acting on the block is 14.8 N.
Economic security
Economic stability
Economic growth
Economic freedom
Economic efficiency
Economic equity
Answer:
1. Dry Beans - 591.75 kg/m^3
2. Flour - 593 kg/m^3
3. Wax - 900 kg/m^3
4. Wet sand - 2039 kg/m^3
5. Chalk - 2499 kg/m^3
6. Talcum Powder - 2776 kg/m^3
7. Copper - 8960 kg/m^3
Explanation:
Make sure your units are the same
