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3 years ago

Explain how you should walk

Physics

2 answers:

Oduvanchick [21]3 years ago

6 0

Answer:

1. Bend your elbows 90 degrees.

2. Partially close your hands, but do not clench them. ...

3.With each step, the arm opposite your forward foot comes straight forward, not diagonally.

4.As the forward foot goes back, the opposite arm comes straight back.

hammer [34]3 years ago

3 0

Answer:

A step by step to walk

Explanation:

One- Make sure your shoes are tied so that you dont trip

Two- Make sure your way is a cleared path so you dont fall or even hurt yourself

three- use both set of lets to go in any direction you want.

Four- when walking make sure to try and keep a steedy pace so that both set of legs are going up and down but in harmony

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An atom of carbon has a radius of 67.0 pm and the average orbital speed of the electrons in it is about 1.3 x 10⁶ m/s.

adoni [48]

Answer :

The least possible uncertainty in an electron's velocity is, $4.32\times 10^{5}m/s$

The percentage of the average speed is, 33 %

Explanation :

According to the Heisenberg's uncertainty principle,

$\Delta x\times \Delta p=\frac{h}{4\pi}$ ...........(1)

where,

$\Delta x$ = uncertainty in position

$\Delta p$ = uncertainty in momentum

h = Planck's constant

And as we know that the momentum is the product of mass and velocity of an object.

$p=m\times v$

or,

$\Delta p=m\times \Delta v$ .......(2)

Equating 1 and 2, we get:

$\Delta x\times m\times \Delta v=\frac{h}{4\pi}$

$\Delta v=\frac{h}{4\pi \Delta x\times m}$

Given:

m = mass of electron = $9.11\times 10^{-31}kg$

h = Planck's constant = $6.626\times 10^{-34}Js$

radius of atom = $67.0pm=67.0\times 10^{-12}m$ $(1pm=10^{-12}m)$

$\Delta x$ = diameter of atom = $2\times 67.0\times 10^{-12}m=134.0\times 10^{-12}m$

Now put all the given values in the above formula, we get:

$\Delta v=\frac{6.626\times 10^{-34}Js}{4\times 3.14\times (134.0\times 10^{-12}m)\times (9.11\times 10^{-31}kg)}$

$\Delta v=4.32\times 10^{5}m/s$

The minimum uncertainty in an electron's velocity is, $4.32\times 10^{5}m/s$

Now we have to calculate the percentage of the average speed.

Percentage of average speed = $\frac{\text{Uncertainty in speed}}{\text{Average speed}}\times 100$

Uncertainty in speed = $4.32\times 10^{5}m/s$

Average speed = $1.3\times 10^{6}m/s$

Percentage of average speed = $\frac{4.32\times 10^{5}m/s}{1.3\times 10^{6}m/s}\times 100$

Percentage of average speed = 33.2 % ≈ 33 %

Thus, the percentage of the average speed is, 33 %

3 0

3 years ago

A student built a fire using coal. the coal started to burn. which statement best describes the energy changes that occurred.

sergiy2304 [10]

Answer:

98% sure the answer is A, as coal, when burning, releases thermal and light energy through the fire.

Explanation:

4 0

3 years ago

Read 2 more answers

An arrow is shot at an angle of 35° and a velocity of 50 m/s. How long does it take to return to its original starting height?

Ostrovityanka [42]

Answer:

4.02 s

Explanation:

From the question given above, the following data were obtained:

Angle of projection (θ) = 35°

Initial velocity (u) = 50 m/s

Acceleration due to gravity (g) = 10 m/s²

Time of flight (T) =?

The time of flight of the arrow can be obtained as follow:

T = 2uSineθ / g

T = 2 × 35 × Sine 35 / 10

T = 70 × 0.5736 / 10

T = 7 × 0.5736

T = 4.02 s

Therefore, the time taken for the arrow to return is 4.02 s

4 0

3 years ago

It takes a student 12.0 minutes to get home from school while riding their bike at 6.7 m/s.

givi [52]

Answer: 289.44km

Explanation:

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4 years ago

Prove the correctness of this equation s=vt + 1/2at

miss Akunina [59]

Answer:

Equation of motion

Explanation:

this equation is known as the second equation of motion and it is used to calculate the distance travelled (s) by a body in time (t), the body having initial velocity (u) and acceleration (a). This equation has four values in it, so if any three values are known, the fourth value can be calculated.

8 0

3 years ago