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babymother [125]
4 years ago
14

In need help I need someone that is really good at physics

Physics
1 answer:
Aloiza [94]4 years ago
5 0
10/70×360°
=51.4°

hope thus helps
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What is meant by the statement,the linear expansivity of copper is 0.000017k
Aliun [14]

Answer:

The change in length per unit length per degree rise in temperature of copper is 0.000017k

Explanation:

Given that :

The linear expansivity of copper is 0.000017k. This simply means that ; for a given copper length, the length of such copper will increase by 0.000017k for every degree rose in temperature of the copper rod.

Therefore, the change in length per unit length per degree rise in temperature (k) is 0.000017

4 0
3 years ago
Which graph uses bars to show data that are broken into intervals?
AnnyKZ [126]

Answer:

A. scatter plot?

Explanation:

I dont really know if I'm right... sorry.

5 0
3 years ago
What is the process of change in a crust due to the motion of hot material underneath?(answer)?
frutty [35]
Im not exactly sure but I think the answer is techtonic plates collide
5 0
3 years ago
true or false? short-wave heat radiation is given off by the earth when the earth absorbs long-wave radiation.
Greeley [361]

Answer:

Hope this helps u, pls mark me brainlist

Explanation:

The sun emits shortwave radiation because it is extremely hot and has a lot of energy to give off. Once in the Earth's atmosphere, clouds and the surface absorb the solar energy. The ground heats up and re-emits energy as longwave radiation in the form of infrared rays.

4 0
3 years ago
A 0.900-V potential difference is maintained across a 1.5m length of 2
Daniel [21]

Answer:

I = 6.42 A

Explanation:

Given that,

Potential difference, V = 0.9 V

Length of the wire, l = 1.5 m

Area of cross section, A=0.6\ mm^2=6\times 10^{-7}\ m^2

We need to find the current in the wire. Let I is current. We can find it using Ohm's law as follows :

V = IR

Where R is the resistance of the wire

I=\dfrac{V}{R}\\\\I=\dfrac{V}{\rho \dfrac{l}{A}}\\\\I=\dfrac{0.9}{5.6\times 10^{-8}\times \dfrac{1.5}{6\times 10^{-7}}}\\\\I=6.42\ A

So, the current in the wire is 6.42 A.

3 0
3 years ago
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