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babymother [125]
4 years ago
14

In need help I need someone that is really good at physics

Physics
1 answer:
Aloiza [94]4 years ago
5 0
10/70×360°
=51.4°

hope thus helps
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The radius of the earth's very nearly circular orbit around the sun is 1.5 1011 m. find the magnitude of the earth's velocity, a
kotykmax [81]
The radius of Earth's circular trajectory is
R=1.5*10^{11} m
The time for the Earth to travel around the Sun is
t=365(days)*24(hours)*3600(seconds) =3.1536*10^7 (s)
Thus the velocity is velocity
v=2\pi R/t =2\pi *1.5*10^{11}/(3.1536*10^{7})=2.99*10^4 (m/s)
From this we can deduce the centripetal acceleration
a=v^2/R =(2.99*10^4)^2/(1.5*10^{11}) =5.96*10^{-3}  (m/s^2)
Angular velocity is
\omega =v/R =(2.99*10^4)/(1.5*10^{11})=2*10^{-7} (rad/s)

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Answer:

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Explanation:

Please find the complete question in the attachment file.

When precipitation accumulated and during the night, the ice on the front windshield of the car also formed. Because after the car was heated up the following morning, the ice has melted easily because the thawing vent, that blasts on the front windshield, were switched on full force. Although there was no attempt to refrigerate the passenger door, the ice there dissolved at the very same price as the ice on the front window, quite significantly endangering the legitimacy of the clarification of a speed at which the snow melts.

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What is an electrostatic phenomenon?​
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Hypothesis why would momentum not be conserved when 2 vehicles collide?
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