Answer:
Speed of the helium after collision = 246 m/s
Explanation:
Given that
Mass of helium ,m₁ = 4 u
u₁=598 m/s
Mass of oxygen ,m₂ = 32 u
u₂ = 401 m/s
v₂ =445 m/s
Given that initially both are moving in the same direction and lets take they are moving in the right direction.
Speed of the helium after collision = v₁
There is no any external force on the masses that is why the linear momentum will be conserve.
Initial linear momentum = Final linear momentum
P = m v
m₁u₁+m₂u₂ = m₁v₁+m₂v₂
598 x 4 + 32 x 401 = 4 x v₁+ 32 x 445
v₁ = 246 m/s
Speed of the helium after collision = 246 m/s
Answer:
37.34372 kg
Explanation:
m = Mass
= Change in temperature
1 denotes water
2 denotes copper
c = Heat capacity
Heat is given by
In this case the heat transfer will be equal
Mass of copper block is 37.34372 kg
Answer:
43.68 J
Explanation:
Distance moved= 7.8 m
Force = 5.6 N
Work Done= Distance moved * Force
= 7.8 *5.6
=43.68 Joules
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