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mestny [16]
3 years ago
14

Combustion is described as an oxidation reaction.

Chemistry
1 answer:
Fiesta28 [93]3 years ago
6 0
Oxygen gas burns during the chemical reaction
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4. A 1.802 gram sample of unknown compound contains 0.721 grams of carbon, 0.121 grams of hydrogen and 0.960 grams of oxygen. Th
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Empirical formula is CH2O

The molecular formula is C6H12O6

Explanation: Please see attachment for explanation

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Consider these phylogenetic trees. The first tree is based on physical characteristics. The second tree is based on structure, g
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Im not 100% sure, but I think the answer is C. If not, Im sorry for bothering you.

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Due Tomorrow!<br><br> What is [OH-] of a solution<br> with a pH of -1.0? <br><br> Answer in M
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M IS A LETTER but N is a letter
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3 years ago
2. List and elaborate on at least two limitations of the 24-hour recall as a
Pavlova-9 [17]

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The correct answer is - may not be typical, and participant burden.

Explanation:

The 24-hour recall is nothing but a retrospective method of diet assessment. In this method, an individual is interviewed about his or her diet consumption during the last 24 hours.

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5 0
3 years ago
A compound is found to be 30.45% n and 69.55 % o by mass. if 1.63 g of this compound occupy 389 ml at 0.00°c and 775 mm hg, what
Charra [1.4K]
1) mass composition

N: 30.45%
O: 69.55%
   -----------
   100.00%

2) molar composition

Divide each element by its atomic mass

N: 30.45 / 14.00 = 2.175 mol

O: 69.55 / 16.00 = 4.346875

4) Find the smallest molar proportion

Divide both by the smaller number

N: 2.175 / 2.175 = 1

O: 4.346875 / 2.175 = 1.999 = 2

5) Empirical formula: NO2

6) mass of the empirical formula

14.00 + 2 * 16.00 = 46.00 g

7) Find the number of moles of the gas using the equation pV = nRT

=> n = pV / RT = (775/760) atm * 0.389 l / (0.0821 atm*l /K*mol * 273.15K)

=> n = 0.01769 moles

8) Find molar mass

molar mass = mass in grams / number of moles = 1.63 g / 0.01769 mol = 92.14 g / mol

9) Find how many times the mass of the empirical formula is contained in the molar mass

92.14 / 46.00 = 2.00

10) Multiply the subscripts of the empirical formula by the number found in the previous step

=> N2O4

Answer: N2O4
3 0
3 years ago
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