A 8.0-m-diameter parachute of a new design is to be used to transport a load from flight altitude to the ground with an average
1 answer:
Answer:
drag coefficient for the parachute is Cd = 1.84177
Explanation:
given data
diameter = 8.0 m
average vertical speed = 3 m/s
total weight of load = 200 N
to find out
drag coefficient for the parachute
solution
we will apply here drag coefficient formula that is express as here
drag coefficient Cd = ......................1
here w is total load and A is area and v is speed
and here ρ = 1.22 kg/cu
put here value we get
Cd =
Cd = 1.84177
drag coefficient for the parachute is Cd = 1.84177
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Answer:
i)ω=3600 rad/s
ii)V=7059.44 m/s
iii)F=1245.8 N
Explanation:
i)
We know that angular speed given as
We know that for one revolution
θ=2π
Given that time t= 2 hr
So
ω=θ/t
ω=2π/2 = π rad/hr
ω=3600 rad/s
ii)
Average speed V
Where M is the mass of earth.
R is the distance
G is the constant.
Now by putting the values
V=7059.44 m/s
iii)
We know that centripetal fore given as
Here given that m= 200 kg
R= 8000 km
so now by putting the values
F=1245.8 N
Answer:
minimum electric power consumption of the fan motor is 0.1437 Btu/s
Explanation:
given data
area = 3 ft by 3 ft
air density = 0.075 lbm/ft³
to find out
minimum electric power consumption of the fan motor
solution
we know that energy balance equation that is express as
E in - E out = ......................1
and at steady state = 0
so we can say from equation 1
E in = E out
so
minimum power required is
E in = W = m =
put here value
E in =
E in =
E in = 0.1437 Btu/s
minimum electric power consumption of the fan motor is 0.1437 Btu/s