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11Alexandr11 [23.1K]
2 years ago
10

A 8.0-m-diameter parachute of a new design is to be used to transport a load from flight altitude to the ground with an average

vertical speed of 3 m/s. The total weight of the load and parachute is 200 N. Determine the approximate drag coefficient for the parachute.
Engineering
1 answer:
S_A_V [24]2 years ago
3 0

Answer:

drag coefficient for the parachute is Cd = 1.84177

Explanation:

given data

diameter = 8.0 m

average vertical speed = 3 m/s

total weight of load = 200 N

to find out

drag coefficient for the parachute

solution

we will apply here drag coefficient formula that is express as here  

drag coefficient Cd = \frac{2w}{\rho v^2A}    ......................1

here w is total load and A is area and v is speed

and here ρ = 1.22 kg/cu

put here value we get  

Cd = \frac{2*4*200}{1.229*5^2*\pi * 3^2}  

Cd = 1.84177

drag coefficient for the parachute is Cd = 1.84177

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the overall heat transfer coefficient of this heat exchanger is 1855.8923 W/m²°C

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v_{w} =\frac{m}{\rho \pi (\frac{d_{2}^{2}-d_{1}^{2}  }{4} )} =\frac{0.3}{998*\pi (\frac{0.025^{2}-0.01^{2}  }{4}) } =0.729m/s

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Re=\frac{v_{w}(d_{2}-d_{1}) }{v} =\frac{0.729*(0.025-0.01)}{1.004x10^{-6} } =10891.4343

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