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3 years ago

6

2,65 Lt de un gas ideal se encuentran a 25°C y 1,2 atm de presión. Si se pasa el gas a un nuevo recipiente de 1,5 litros a una t

emperatura de 72°C, ¿Cuál es la nueva presión del gas?

1 answer:

11111nata11111 [884]3 years ago

4 0

Answer:

2.5 atm

Explanation:

P2 = 1.2 atm x 2.65 L x 345 K / 1.5 L x 298 K

Esto debería ser igual...

2.45 atm (personajes importantes)

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Question 6 of 10

KengaRu [80]

Answer:

option C

Explanation:

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8 0

3 years ago

How does the molecular formula of a compound differ from the empirical formula? Can a compound’s empirical and molecular formula

Y_Kistochka [10]

Molecular is every element present in the compound eg C2H6, empirical is the smallest whole number ratio of elements in a compound so that would be CH3 as you divide by the highest common factor. Some compounds only have 1 formula if they are simple or have no common factors. Eg methane, CH4 is its molecular and empirical because its the simplest whole number ratio and includes every element in the molecule

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2 years ago

a concentration solution of H2so4 is 59.4% by mass (m/m) and has a density of 1.83 g/mL. How many mL of the solution would be re

Blababa [14]

Answer: 41.5 mL

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

$Molarity=\frac{n}{V_s}$

where,

n = moles of solute

$V_s$ = volume of solution in L

Given : 59.4 g of $H_2SO_4$ in 100 g of solution

moles of $H_2SO_4=\frac{\text {given mass}}{\text {molar mass}}=\frac{59.4g}{98g/mol}=0.61$

Volume of solution = $\frac{\text {mass of solution}}{\text {density of solution}}=\frac{100g}{1.83g/ml}=54.6ml$

Now put all the given values in the formula of molality, we get

$Molality=\frac{0.61\times 1000}{54.6ml}=11.2M$

To calculate the volume of acid, we use the equation given by neutralisation reaction:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of stock acid which is $H_2SO_4$

$M_2\text{ and }V_2$ are the molarity and volume of dilute acid which is $H_2SO_4$

We are given:

$M_1=11.2M\\V_1=mL\\M_2=0.30M\\V_2=1550mL$

Putting values in above equation, we get:

$11.2\times V_1=0.30\times 1550\\\\V_1=41.5mL$

Thus 41.5 mL of the solution would be required to prepare 1550 mL of a .30M solution of the acid

4 0

3 years ago

What is the mole ratio of NO2 to O2

Mazyrski [523]

The mole ratio is 4 NO2 to 3 O2; 4:3

8 0

3 years ago

Which condition must be met in order for an equation to be balanced?

olga55 [171]

Answer:

The elements in the reactants are the same as the elements in the products.

Explanation:

You can't have more or less elements or atoms, but you also can't just have the same number of atoms because then it could be different elements, which can't happen.

5 0

3 years ago

Read 2 more answers