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deff fn [24]
3 years ago
6

2,65 Lt de un gas ideal se encuentran a 25°C y 1,2 atm de presión. Si se pasa el gas a un nuevo recipiente de 1,5 litros a una t

emperatura de 72°C, ¿Cuál es la nueva presión del gas?
Chemistry
1 answer:
11111nata11111 [884]3 years ago
4 0

Answer:

2.5 atm

Explanation:

P2 = 1.2 atm x 2.65 L x 345 K / 1.5 L x 298 K

Esto debería ser igual...

2.45 atm (personajes importantes)

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A sample obtained from the national bureau of standards had a calibrated weight of 20.000. When it was used tocalibrate a studen
melisa1 [442]

Answer : The measurements are both precise and accurate.

Explanation :

Accuracy : It is defined as the closeness of a measured value to a standard or known value.

For Example: If the mass of a substance is 50 kg and one person weighed 48 kg and another person weighed 55 kg. Then, the weight measured by first person is more accurate.

Precision : It is defined as the closeness of two or more measurements to each other.

For Example: If you weigh a given substance five times and you get 1.8 kg each time. Then the measurement is said to be precise.

Level of precision is determined by the maximum number of decimal places.

When the level of precision is very very less, the measurement can be considered as most precise and most accurate.

As we are given the standard value of the sample is 20.000 and the values measured by the balance are, 19.995, 20.005, 20.001.

Since these three values are in the range of +/- 0.005 from one another. So, we can say that the measurements are both precise and accurate.

Hence, the measurements are both precise and accurate.

3 0
4 years ago
g cr2o3 molar mass compound containing chromium and silicon contains 73.52 mass percent chromium. Determine its empirical formul
gavmur [86]
Ggggggggggggggggggggg
4 0
3 years ago
Tin reacts with fluorine to form two different compounds, A and B. Compound A contains 38.5 g of tin for each 12.3 g of fluorine
Hatshy [7]
Tin to Fluorine mass ratios:
1) For compound A:
38.5/12.3
= 3.13
2) For compound B:
56.5/36.2
= 1.56
The lowest whole number mass ratio is 2. It cannot be 1 because it is less than that required for compound B.
5 0
3 years ago
Read 2 more answers
How much energy must be added to a 1 kg piece of gold with a specific heat of 130 j/kg to increase its temperature from 20 c to
Lorico [155]

Q = 10.4 \; \text{kJ}

The specific heat of a material gives the energy it takes to increase the temperature of one unit mass of the material by one unit temperature. The SI unit for specific heat c is therefore \text{J} /\text{kg} \cdot \textdegree{\text{C}}.

The formula relating the energy required to raise the temperature of m grams of a substance with specific energy c by \Delta T degrees is

Q= c \cdot m \cdot \Delta T

The question provides the following information:

  • c = 130\; \text{J} /\text{kg} \cdot \textdegree{\text{C}} for gold
  • m= 1 \; \text{kg}
  • \Delta T = 100 \textdegree{\text{C}} - 20 \textdegree{\text{C}} = 80 \textdegree{\text{C}}

Apply the formula:

\begin{array}{ccc} Q & = & c \cdot m \cdot \Delta T\\  & = & 130 \; \text{J} \cdot \text{kg}^{-1} \cdot \textdegree{\text{C}}^{-1} \times 1 \; \text{kg} \times 80 \;  \textdegree{\text{C}}\\ & = & 1.04 \times 10^{4} \;\text{J}\\ & = & 10.4 \; \text {kJ} \end{array}

7 0
4 years ago
Describe the appearance of the material. Include its color and state (solid or liquid). Pour ¼ cup of water into a small, clear
Alex777 [14]

<u>Answer:</u>

<em>Here the given material is taken and mixed with water.</em>

<u>Explanation:</u>

The amount of material and water taken are same. Hence if it is not soluble in water it should make a dense and flowy paste like material and if it is soluble in water it should this and thicker density of water should remain.

If the amount of water that we are taking is more than the material will float in water if it is not soluble and lighter than water or would sink if it is heavier than water.

5 0
3 years ago
Read 2 more answers
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