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deff fn [24]
3 years ago
6

2,65 Lt de un gas ideal se encuentran a 25°C y 1,2 atm de presión. Si se pasa el gas a un nuevo recipiente de 1,5 litros a una t

emperatura de 72°C, ¿Cuál es la nueva presión del gas?
Chemistry
1 answer:
11111nata11111 [884]3 years ago
4 0

Answer:

2.5 atm

Explanation:

P2 = 1.2 atm x 2.65 L x 345 K / 1.5 L x 298 K

Esto debería ser igual...

2.45 atm (personajes importantes)

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For any molecule at the surface the resulting surrounding forces equal zero
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False is the correct answer
4 0
2 years ago
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Draw a mechanism for this reaction. 5-hydroxypentanoic acid forms 2-oxanone in the presence of acid. draw all missing reactants
Licemer1 [7]

Answer: -

The first step involves protonation of the carbonyl oxygen.

After protonation, the Alcohol oxygen now attacks the carbon of the carbonyl.

Thus a six membered ring is formed with 5 carbon atoms and 1 oxygen atom. The 1st position carbon atom has 2 OH groups.

One of these gets again protonated.

This leaves as water. With the loss of the H+, there results a carbonyl at 1 position.

Thus 5-hydroxypentanoic acid forms a lactone or 2-oxanone in presence of acid.

3 0
3 years ago
An unknown liquid is composed of 34.31% c, 5.28% h, and 60.41% i. The molecular weight is 210.06 amu. What is the molecular form
ozzi

In an unknown liquid, the percentage composition with respect to carbon, hydrogen and iodine is 34.31%, 5.28% and 60.41% respectively.

Let the mass of liquid be 100 g thus, mass of carbon, hydrogen and oxygen will be 34.31 g, 5.28 g and 60.41 g respectively.

To calculate molecular formula of compound, convert mass into number of moles as follows:

n=\frac{m}{M}

Molar mass of carbon, hydrogen and iodine is 12 g/mol, 1 g/mol and 126.90 g/mol.

Taking the ratio:

C:H:I=n_{C}:n_{H}:n_{I}

Putting the values,

C:H:I=\frac{34.31 g}{12 g/mol}:\frac{5.28 g}{1 g/mol}:\frac{60.41 g}{126.90 g/mol}=6:11:1

Thus, molecular formula of compound will be C_{6}H_{11}I.

4 0
3 years ago
. Given the following pOH's, calculate the pH for the solution:
ryzh [129]

Answer:

a) pH = 9.82     b) pH = 1.65

a) pOH = 7.8     b) pOH = 4.45

Explanation:

pOH + pH = 14 for all of these solutions.

3 0
3 years ago
Oxalic acid, H2C2O4, reacts
Dominik [7]

Answer:0.005M

Explanation:

First deduce the oxidation and reduction half equations and from that obtain the balanced redox reaction equation. From that, the number of moles of reacting species are seen from the stoichiometry of the reaction from which the number of moles of oxalate is obtained and substituted to obtain the molar concentration of oxalate.

6 0
3 years ago
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