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Lunna [17]
3 years ago
12

What are the major weather fronts? How do they differ from each other?

Physics
1 answer:
dmitriy555 [2]3 years ago
3 0

Answer:

they differ each other bc it is a lot of with earth quakes and everything.

Explanation:

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After watching a video about submarines, Jamil wants to learn more about the ocean. which question could be answered through sci
SOVA2 [1]
<span>Submarines are equipped with water tanks called ballast tanks that fill up to submerge the vessel. Emptying the tanks and filling them with air causes the submarine to surface.</span>
5 0
3 years ago
To what circuit element is an ideal capacitor equivalent in circuits for which the currents and voltages are constant with time?
Vanyuwa [196]

Explanation:

Since the current flowing through an ideal capacitor is described by equation:

i_{C}=C\frac{dV}{dt}

for voltage across the capacitor constant with time the current is:

i_{C}=\frac{d(Constant)}{dt}=0

Open switch has this characteristics (Constant voltage and zero current).  

3 0
3 years ago
The magnetic field in the region between the poles of an electromagnet is uniform at any time, (1 point) but is increasing at th
olga nikolaevna [1]

Answer:

B)

The magnitude of induced emf in the conducting loop is 0.99 mV.

Explanation:

Rate of increase in magnetic field per unit time = 0.090 T/s

Area of the conducting loop = 110 cm^2 = 0.0110 m^2

Electromagnetic induction is the production of an emf or voltage in a coil of wire due to a changing magnetic field through the coil.

Induced e.m.f is given as:

EMF = (-N*change in magnetic field/time)*Area

EMF = rate of change of magnetic field per unit time * Area

EMF = 0.090 * 0.0110

EMF = 0.00099 V

EMF = 0.99 mV

5 0
3 years ago
The terminals of a 0.70 Vwatch battery are connected by a 80.0-m-long gold wire with a diameter of 0.200 mm What is the current
Molodets [167]

Answer:

I = 11.26 mA

Explanation:

given,

V = 0.7 V           length = 80 m

diameter   = 0.2 mm = 0.02 cm

radius = 0.01 × 10⁻² m

resistance = \dfarc{\rho l}{A}

ρ for gold wire = 2.44 × 10⁻⁸ ohm-m at 20 °C

A = cross sectional area = π r² = π (0.01 × 10⁻² )²

    = 31.4× 10⁻⁹ m²

resistance = \dfarc{2.44\times 10^{-8} \times 80}{31.4\times 10^{-9}}

R = 62.165 Ω

I = \dfrac{V}{R}

I = \dfrac{0.7}{62.165}

I = 11.26 mA

8 0
3 years ago
A bird is flying with a speed of 18.0 m/s over water when it accidentally drops a 2.00 kg fish. If the altitude of the bird is 5
Alina [70]
Here we go.
My abbreviations; KE = Kinetic Energy; GPE = Gravitational Potential Energy.

So first off, we know the fish has KE right when the bird releases it. Why? Because it has horizontal velocity after released! So let’s calculate it:
KE = 1/2(m)(V)^2
KE = 1/2(2)(18)^2
KE = 324 J

Nice!
We also know that the fish has GPE at its maximum height before release:
GPE = mgh
GPE = (2)(9.81)(5.40)
GPE = 105.95 J

Now, based on the *queue dramatic voice* LAW OF CONSERVATION OF ENERGY, we know all of the initial energy of the fish will be equal to the amount of final energy. And since the only form of energy when it hits the water is KE, we can write:
KEi + GPEi = KEf
(Remember - we found the initial energies before!)
(324) + (105.95) = KEf
KEf = 429.95J
And that’s you’re final answer! Notice how this value is MORE than the initial KE from before (324 J) - this is because all of the initial GPE from before was transformed into more KE as the fish fell (h decreased) and sped up (V increased).

If this helped please like it and comment!
4 0
3 years ago
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