<span>True
</span><span>True
</span><span>False*
</span><span>False*
</span><span>True
</span><span>True
</span><span>False
A,B,AB,O
10.)?
11.)</span><span>water
carbon dioxide
12.)</span><span>geocentric
</span>13.)<span>Juptier</span>
Answer:
The coastal zone is not a stable and constant environment, but a dynamic place that can change rapidly in response to natural processes such as seasonal weather patterns. Waves, winds, currents, tides and storms are the major forces on the coast.
Explanation:
Answer:
22.5 m
Explanation:
From the question given above, the following data were obtained:
Initial velocity (u) = 30 m/s
Time (t) = 1.5 s
Final velocity (v) = 0 m/s
Distance (s) =?
The distance to which the car move before stopping from the time the driver applied the brake can be obtained as follow:
s = (u + v)t/2
s = (30 + 0)1.5 / 2
s = (30 × 1.5) / 2
s = 45 / 2
s = 22.5 m
Thus, the car will move to a distance of 22.5 m before stopping from the time the driver applied the brake.
Answer:
2.78 m
Explanation:
At the peak, the velocity is 0.
Given:
a = -1.6 m/s²
v₀ = 2.98 m/s
v = 0 m/s
x₀ = 0 m
Find:
x
v² = v₀² + 2a(x - x₀)
(0 m/s)² = (2.98 m/s)² + 2(-1.6 m/s²) (x - 0 m)
x = 2.775 m
Rounded to 3 sig-figs, the astronaut halloweener reaches a maximum height of 2.78 meters.
During upward projection the final velocity is zero, and the gravitational acceleration is -10 m/s² (against the gravity).
Therefore; using the equation;
S = 1/2gt² + ut
Where s is the height h, g is gravitational acceleration, and t is the time and u is the initial velocity u, is 16 ft/s.
Thus; h= 1/2(-10)t² + 16t
We get; h = -5t² + 16t
Therefore; the quadratic equation is 5t² - 16t + h =0
