How many moles of aluminum are needed to react with 3.6 mol of FeO? 2Al(s) + 3FeO(s) ----> 3Fe(s) + Al^2O^3(s)

Many common liquids have boiling points that are less than 110°C, whereas most metals are solids at room temperature and have mu

Semmy [17]

Answer:

1. 315.4 K

2. 1560 °C

Explanation:

To convert from celsius to Kelvin, the following formula can be used:

T(K) = T(°C) + 273

Where:

T(K) => Temperature in Kelvin

T(°C) => Temperature in degree celsius

1. Determination of the temperature in Kelvin.

Temperature (T) in °C = 42.4 °C.

Temperature (T) in K =?

T(K) = T(°C) + 273

T(K) = 42.4 °C + 273

T(K) = 315.4 K

2. Determination of the temperature in degree Celsius.

Temperature (T) in K = 1833 K

Temperature (T) in °C =?

T(K) = T(°C) + 273

1833 = T(°C) + 273

Collect like terms

T(°C) = 1833 – 273

T(°C) = 1560 °C

7 0

3 years ago

The average American is looking at their phone for 6.25 hours a day. How many hours will the average American spend on their pho

julia-pushkina [17]

Answer:

177253.125hrs

Explanation:

Given parameters:

Number of hours spend per day on phone = 6.25hrs

Unknown:

Average hours pend by an average American if they lived for 77.7yrs

Solution:

Let us find the number of hours an average American spends on their phone per year;

there are 365days in a year

Number of hours = 365 x 6.25 = 2,281.25hrs

Now, if they lived for 77.7yrs;

They will spend = 77.7 x 2,281.25 = 177253.125hrs

8 0

2 years ago

Aqueous sulfuric acid will react with solid sodium hydroxide to produce aqueous sodium sulfate and liquid water . Suppose 6.9 g

satela [25.4K]

Answer:

$5.6gNa_2SO_4$

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

$2NaOH(aq)+H_2SO_4(aq)\rightarrow Na_2SO_4(aq)+2H_2O(l)$

Therefore, since the masses of both of the reactants are given, one computes the available moles of sulfuric acid and those moles of it consumed by the sodium hydroxide as shown below:

$n_{H_2SO_4}^{available}=6.9gH_2SO_4*\frac{1molH_2SO_4}{98gH_2SO_4}=0.0704molH_2SO_4\\n_{H_2SO_4}^{consumed\ by\ NaOH}=3.14gNaOH*\frac{1molNaOH}{40gNaOH}*\frac{1molH_2SO_4}{2molNaOH}=0.04molH_2SO_4$

In such a way, since there is more available sulfuric acid than it that is consumed, the sodium hydroxide is the limiting reagent, consequently, the maximum mass of sodium sulfate turns out:

$m_{Na_2SO_4}=0.04molH_2SO_4*\frac{1molNa_2SO_4}{1molH_2SO_4} *\frac{142.04gNa_2SO_4}{1molNa_2SO_4}=5.6gNa_2SO_4$

Best regards.

5 0

2 years ago

Please helpppp

AysviL [449]

Answer:

3

Explanation:

4 0

3 years ago

If 17. 6 g of hcl are used to produce a 14. 5 l solution, what is the ph of the solution?.

kati45 [8]

This problem is providing us with the mass of hydrochloric acid and the volume of solution and asks for the pH of the resulting solution, which turns out to be 1.477.

<h3>pH calculations</h3>

In chemistry, one can calculate the pH of a solution by firstly obtaining its molarity as the division of the moles of solute by the liters of solution, so in this case for HCl we have:

$M=\frac{17.6g*\frac{1mol}{36.46g} }{14.5L} \\\\M=0.0333 M$

Next, due to the fact that hydrochloric acid is a strong acid, we realize its concentration is nearly the same to the released hydrogen ions to the solution upon ionization. Thereby, the resulting pH is:

$pH=-log(0.0333)\\\\pH=1.477$

Which conserves as much decimals as significant figures in the molarity.

Learn more about pH calculations: brainly.com/question/1195974

3 0

1 year ago