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Vladimir [108]
3 years ago
15

What is the formula to calculate the thickness of a test tube?​

Physics
1 answer:
Maslowich3 years ago
4 0

Answer:

Having the inside dimensions (ID) and the outside dimensions (OD) will allow you to figure out the wall thickness on tubing. You would need to subtract the ID from the OD and then divide by two. This number is the wall thickness.

Explanation:

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Are outer planets gaseous
bija089 [108]

Answer:

Yes

Explanation:

The four outer planets are all gas giants made primarily of hydrogen and helium. They have thick gaseous outer layers and liquid interiors.

6 0
2 years ago
If you were to be drawn into a black hole, what would happen? To the black hole, not to you.
love history [14]

Answer:

It grows

Explanation:

The blacks holes will absorb

Me hoizontally stretching me like a noodle by the spaghtification process,thus growing bigger.

7 0
3 years ago
The larger the push, the larger the change in velocity. This is an example of Newton's Second Law of Motion which states that th
Mars2501 [29]

Answer:

According to Newton's 2nd law

The force acting on a body produces acceleration in its direction which is directly propotional to the force but inversly propotinal to the mass of tbe body.

Explanation:

a = F/m

F = ma

Where( F) is force (m) is mass and (a) is acceleration.

6 0
3 years ago
Which of these is a characteristic of the Milky Way galaxy
IRINA_888 [86]

Answer:

A

Explanation:

3 0
2 years ago
A football punker attempts to kick the football so that it lands on the ground 67.0 m from where it is kicked and stays in the a
Flauer [41]

To solve this problem we will apply the linear motion kinematic equations. We will find the two components of velocity and finally by geometric and vector relations we will find both the angle and the magnitude of the vector. In the case of horizontal speed we have to

v_x = \frac{x}{t}

v_x = \frac{67}{4.5}

v_x = 14.89m/s

The vertical component of velocity is

-h = v_y t -\frac{1}{2} gt^2

Here,

h = Height

g = Gravitational acceleration

t = Time

v_y = Vertical component of velocity

-1.23 = v_y(4.5)-\frac{1}{2} (9.8)(4.5)^2

-1.23= 4.5v_y - 99.225

v_y = 21.77m/s

The direction of the velocity will be given by the tangent of the components, then

tan\theta = \frac{v_y}{v_x}

\theta = tan^{-1} (\frac{21.77}{14.89})

\theta = 55.59\°

The magnitude is given vectorially as,

|V| = \sqrt{v_x^2+v_y^2}

|V| = \sqrt{14.89^2 +21.77^2}

|V| = 26.37m/s

Therefore the angle is 55.59° and the velocity is 26.37m/s

6 0
2 years ago
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