Explanation:
It is given that,
Diameter of the peach pie, d = 9 inches
Radius of the pie, r = 4.5 inches
The tray is rotated such that the rim of the pie plate moves through a distance of 183 inches, d = 183 inches
Let is the angular distance that the pie plate has moved through.
It is given by :
Since, 1 radian = 57.29 degrees
Since, 1 radian = 0.159155 revolution
Hence, this is the required solution.
Answer:
The shortest transverse distance between a maximum and a minimum of the wave is 0.1638 m.
Explanation:
Given that,
Amplitude = 0.08190 m
Frequency = 2.29 Hz
Wavelength = 1.87 m
(a). We need to calculate the shortest transverse distance between a maximum and a minimum of the wave
Using formula of distance
Where, d = distance
A = amplitude
Put the value into the formula
Hence, The shortest transverse distance between a maximum and a minimum of the wave is 0.1638 m.