Answer:
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Explanation:
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Find the toughness (or energy to cause fracture) for a metal that experiences both elastic and plastic deformation. Assume Equat
ion 6.5 for elastic deformation, that the modulus of elasticity is 172 GPa (25 ´ 106 psi), and that elastic deformation terminates at a strain of 0.01. For plastic deformation, assume that the relationship between stress and strain is described by Equation 6.19, in which the values for K and n are 6900 MPa (1 ´ 106 psi) and 0.30, respectively. Furthermore, plastic deformation occurs between strain values of 0.01 and 0.75, at which point fracture occurs.
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Answer:
Current Relative Humidity is 29.623
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Current Temperature,
Dew point temperature,
Solution:
Now, in order to calculate the Relative Humidity, RH, we use the given formula:
where
a = 17.625
b = 237.7
Now, using the above formula and given values:
On solving the above eqn, we get:
RH = 29.623