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Lady_Fox [76]
3 years ago
6

Find the toughness (or energy to cause fracture) for a metal that experiences both elastic and plastic deformation. Assume Equat

ion 6.5 for elastic deformation, that the modulus of elasticity is 172 GPa (25 ´ 106 psi), and that elastic deformation terminates at a strain of 0.01. For plastic deformation, assume that the relationship between stress and strain is described by Equation 6.19, in which the values for K and n are 6900 MPa (1 ´ 106 psi) and 0.30, respectively. Furthermore, plastic deformation occurs between strain values of 0.01 and 0.75, at which point fracture occurs.

Engineering
1 answer:
PtichkaEL [24]3 years ago
7 0

Answer:

Detailed solution is attached below in three simple steps the problem is solved.

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Con que otro nombre se le conoce a los delitos informaticos
kow [346]
Repuesto: Cyberdelito
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3 years ago
Given a force of 72 lbs at a distance of 15 ft, calculate the moment produced.​
Elis [28]

Answer:

1425.78 N.m

Explanation:

Moments of force is calculated as ;

Moments= Force * distance

M= F*d

The S.I unit for moment of force is Newton-meter (N.m)

Given in the question;

Force = 72 lbs

1 pound = 4.45 N

72 lbs = 4.45 * 72=320.4 N

Distance= 15 ft

1ft= 0.3048 m

15 ft = 15*0.3048 = 4.57 m

d= 4.57 m

M= F*d

M=320.4*4.57 =1425.78 N.m

5 0
4 years ago
Steel grade AISI 1045 contains 4.5% carbon. a)-True b)- False
yarga [219]

Answer:

False

Explanation:

According to the AISI (SAE) statements the last two numbers of the designation indicates the porcentage of carbon in the steel. And the firs numbers indicate the most important alloy alements.

In the case of the AISI 1045 indicates that the composition of this steel is 0,45% of carbon.

4 0
3 years ago
Explain difference(s) between strength, hardness and toughness.
harkovskaia [24]

Explanation:

Step1

Strength is the maximum stress induces in the material under applied load condition. More the strength more will be ability to sustain load. Strength can be measured from tensile test. It has same unit as stress. Generally ductile material has more strength as compare to brittle material.

Step2

Hardness is the resistance to scratch on the material under given load condition. More the hardness more will be the resistance towards scratching of material. Hardness can be measured by Rockwell or Birnell hardness test. This property of metal is opposite to the strength.

Step3

Toughness is the ability to absorb energy under given loading condition up to its fracture point. It is a type of strain energy that is stored in the metal. Generally ductile metal has more toughness as compare to brittle.

4 0
4 years ago
For this lab you will be creating a auto-expanding dynamic-array. This array will explicitly hold std library strings. As with a
Inessa05 [86]

Answer:

Explanation:

Program is divided into 3 files. stringVector.h , stringVectory.cpp (implementation file) and main.cpp (testing file)

stringVector.h

#include<iostream>

using namespace std;

class stringVector {

private:

string * data;

unsigned length;

unsigned allocated_length;

public:

stringVector();

virtual ~stringVector();

unsigned size();

unsigned capacity();

void reserve(unsigned new_size);

bool empty();

void append(string new_data);

void swap(unsigned pos1, unsigned pos2);

stringVector &operator = (stringVector const &rhs);

string& operator[](unsigned position);

void sort();

};

stringVector.cpp

#include<iostream>

#include<stdexcept>

#include"stringVector.h"

stringVector::stringVector()

{

data = NULL;

length = 0;

allocated_length = 0;

}

stringVector::~stringVector()

{

delete [] data;

}

unsigned stringVector::size()

{

return length;

}

unsigned stringVector::capacity()

{

return allocated_length;

}

void stringVector::reserve(unsigned new_size)

{

string *temp = new string[new_size]; // Create a new array

 

/*Copy the contents of the array*/

for(int i =0; i < new_size; i++){

if(i < length){

temp[i] = data[i];

}

else

break;

}

 

delete []data ;// Delete previous array

data = temp;

allocated_length = new_size;

if(length > new_size){

length = new_size;

}

}

bool stringVector::empty(){

return (length == 0) ? true : false;

}

void stringVector::append(string new_data)

{

string *temp = NULL;

if(length == allocated_length){

if(allocated_length == 0){

data = new string[10];

allocated_length = 10;    

}

else{

temp = new string[2 * allocated_length]; // Create a new array with double the size

for(int i = 0; i < length ; i++){

temp[i] = data[i];

}

allocated_length = 2 * allocated_length;

 

if(data != NULL)

delete []data;

data = temp;

}

}

data[length] = new_data;

length++;

}

void stringVector::swap(unsigned pos1, unsigned pos2)

{

string str;

if((pos1 >= length) || (pos2 >= length)){

cout << "Index Out of bounds" << endl;

return;

}

str = data[pos1];

data[pos1] = data[pos2];

data[pos2] = str;

}

stringVector& stringVector::operator = (stringVector const &rhs)

{

delete [] data;

length = rhs.length;

allocated_length = rhs.allocated_length;

this->data = new string[allocated_length];

for(int i=0 ; i < length; i++)

this->data[i] = rhs.data[i];

}

string& stringVector::operator[](unsigned position)

{

if(position > length){

throw std::out_of_range("Position out of range");

}

return data[position - 1];

}

void stringVector::sort()

{

string str;

for(int i= (length - 1) ; i > 0; i--){

for(int j = 0; j < i; j++){

if(data[j].compare(data[j+1]) > 0){

//Swap

str = data[j];

data[j] = data[j+1];

data[j+1] = str;

}

}

}

}

main.cpp

#include<iostream>

#include<stdexcept>

#include"stringVector.h"

void printVector(stringVector &);

int main()

{

stringVector vector;

string str1("California");

string str2("Alabama");

string str3("Oklahoma");

string str4("Texas");

vector.append(str1);

vector.append(str2);

vector.append(str3);

vector.append(str4);

cout << vector.size() << " - " << vector.capacity() << endl;

printVector(vector);

cout << endl;

vector.reserve(3);

cout << vector.size() << " - " << vector.capacity() << endl;

printVector(vector);

cout << endl;

vector.append(str4);

cout << vector.size() << " - " << vector.capacity() << endl;

printVector(vector);

cout << endl << "Copied vector : " << endl;

stringVector vector2 = vector;

printVector(vector2);

cout << endl;

vector.sort();

cout << "Vector 1 after sorting" << endl;

printVector(vector);

return 0;

}

void printVector(stringVector &vec)

{

cout << "Vector : ";

for(int i = 1 ; i <= vec.size(); i++){

cout << vec[i] << " ";

}

cout << endl;

}

OUTPUT:

[[email protected] cppProg3]$ ./main

4 - 10

Vector: California Alabama Oklahoma Texas

3 -3

Vector: California Alabama Oklahoma

4 - 6

Vector: California Alabama Oklahoma Texas

Copied Vector:

Vector: California Alabama Oklahoma Texas

Vector 1 after sorting

Vector: Alabama California Oklahoma Texas

8 0
3 years ago
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