Find the toughness (or energy to cause fracture) for a metal that experiences both elastic and plastic deformation. Assume Equat
ion 6.5 for elastic deformation, that the modulus of elasticity is 172 GPa (25 ´ 106 psi), and that elastic deformation terminates at a strain of 0.01. For plastic deformation, assume that the relationship between stress and strain is described by Equation 6.19, in which the values for K and n are 6900 MPa (1 ´ 106 psi) and 0.30, respectively. Furthermore, plastic deformation occurs between strain values of 0.01 and 0.75, at which point fracture occurs.
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Answer:
Matlab code with step by step explanation and output results are given below
Explanation:
We have to construct a Matlab function that creates a row vector "countValues" with elements 1 to endValue. That means it starts from 1 and ends at the value provided by the user (endValue).
function countValues = CreateArray(endValue)
% Here we construct a row vector countValues from 1:endValue
countValues = 1:endValue;
% then we transpose this row vector into column vector
countValues = countValues';
end
Output:
Calling this function with the endValue=11 returns following output
CreateArray(11)
ans =
1
2
3
4
5
6
7
8
9
10
11
Hence the function works correctly. It creates a row vector then transposes it and makes it a column vector.
