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Yuliya22 [10]
2 years ago
11

How many atoms will be in a 0.010 gram sample of aluminum

Chemistry
1 answer:
Brums [2.3K]2 years ago
5 0
Um let me think ummm dang hold on bro i will be right back ok 
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Zinc reacts with iron (iii) chloride yielding zinc chloride plus iron
olasank [31]

Answer:

I don't see a specific question, so I'll make a few comments and hope that answers the reason for the post.

Explanation:

Zinc(Zn) does react with iron chloride, since zinc is a more reactive metal than the iron.

When Zn is introduced to an iron (III) chloride solution, the Zn disoplaces the Fe atom in a displacement reaction.

The chemical equation of the reaction:

Zn + Fe(III)Cl3 → ZnCl3 + Fe

Energy is often realeased in this type of reaction, since the resulting chemical products have a lower energy that the reactants.

There are several metals more reactive than iron.  One of the more interesting examples of a highly exothermic reaction with iron chloride (rust) is the reaction of aluminum with iron chloride.  `This is highly exothermic and is labelled a thermite reaction.  It provides a spectacular flame that is not enough to weld railroad tracks together.

6 0
2 years ago
Using the correct answer from Part B, calculate the volume of a rectangular prism with a length of 5.6 cm, a width of 2.1 cm, an
son4ous [18]
So the question is asking to compute the volume of a rectangular prism with a length of 5.6 cm,  width of 2.1 cm and a height of 6.6 cm, and base on the said given and using the formula in getting the volume of a rectangular prism, the volume 77.62 cm^3. I hope this would help.
3 0
3 years ago
Read 2 more answers
What sample size (grams) of Na3PO4 (FW 164.00) known to be 50.00% pure should be used to consume exactly 40.00 mL of 0.1000 M HC
Mkey [24]

Answer:

0.109 g.

Explanation:

Equation of the reaction:

Na3PO4 + 3HCl --> 3NaCl + H3PO4

Number of moles of HCl = molar concentration × volume

= 0.1 × 0.04

= 0.004 mol.

By stoichiometry, 1 mole of Na3PO4 neutralises 3 moles of HCl. Therefore, number of moles of Na3PO4 = 0.004/3

= 0.0013 mol

Mass of Na3PO4 = molar mass × number of moles

= 0.0013 × 164

= 0.219 g

Since 50% of Na3PO4 was present in the sample. Let 100 g be the total mass of the substance

= 0.219 × 50 g/100 g

= 0.109 g.

3 0
3 years ago
Can someone help me... (just give me the answers please
ExtremeBDS [4]
Chlorine formula is CI2
7 0
2 years ago
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Which is a symbol that represents SI units for temperature.
dsp73

Answer:

A.'C

Explanation:

Please answer my question

5 0
3 years ago
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