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Anni [7]
3 years ago
13

Is it possible for surfers to use dynamite to produce water waves that are suitable for surfing

Physics
1 answer:
hammer [34]3 years ago
7 0

if they had a suitable amount to cause an interruption in the waves so huge and vast that it makes waves..... it depends because you can have any amount and get different results any day though

hope this helps plz mark me brainliest

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The height of the tide measured at a seaside community varies according to the number of hours t after midnight. If the height h
antoniya [11.8K]

Explanation:

Given that, the height of the tide measured at a seaside community varies according to the number of hours t after midnight. The height is given by the equation as :

h=-\dfrac{1}{2}t^2+6t-9

When the tide first be at 6 ft, put h = 6 ft in above equation as :

-\dfrac{1}{2}t^2+6t-9=6

-t^2+12t-18=0

On solving the above equation to find the value of t. It is equal to :

t = 3.551 seconds

or

t = 8.449 seconds

So, the tide of 6 ft is at  3.551 seconds and 8.449 seconds. Hence, this is the required solution.

6 0
3 years ago
As we increase the frequency of this light, but do not vary anything else (there may be more than one correct answer),
solong [7]
The answer is c hope this helps
7 0
3 years ago
Is the substance an atom or a molecule?
ANTONII [103]

Answer:

A pair of oxygen atoms is a molecule of oxygen. A molecule is the smallest particle of a substance that exists independently. Molecules of most elements are made up of only one of atom of that element. Oxygen, along with nitrogen, hydrogen, and chlorine are made up of two atoms.

Explanation:

6 0
3 years ago
A 165 N object is supported by three cables(T1, T2 and T3), of which T1 and T2 are making angles θ1 = 52o and θ2 = 39o as shown
Liono4ka [1.6K]

Answer:

?Tension in string 2, T2 (in Newton) =

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3 0
2 years ago
A student is examining a bacterium under the microscope. The E. coli bacterial cell has a mass of m = 0.900 fg (where a femtogra
just olya [345]

Answer:

9.73 x 10⁻¹⁰ m

Explanation:

According to Heisenberg uncertainty principle

Uncertainty in position x uncertainty in momentum ≥ h / 4π

Δ X x Δp ≥ h / 4π

Δp = mΔV

ΔV = Uncertainty in velocity

= 2 x 10⁻⁶ x 3 / 100

= 6 x 10⁻⁸

mass m = 0.9 x 10⁻¹⁵ x 10⁻³ kg

m = 9 x 10⁻¹⁹

Δp = mΔV

= 9 x 10⁻¹⁹ x 6 x 10⁻⁸

= 54 x 10⁻²⁷

Δ X x Δp ≥ h / 4π

Δ X x  54 x 10⁻²⁷ ≥ h / 4π

Δ X = h / 4π x 1 /  54 x 10⁻²⁷

= \frac{6.6\times10^{-34}}{4\times3.14\times54\times10^{-27}}

= 9.73 x 10⁻¹⁰ m

7 0
3 years ago
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