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3 years ago

Is it possible for surfers to use dynamite to produce water waves that are suitable for surfing

1 answer:

7 0

if they had a suitable amount to cause an interruption in the waves so huge and vast that it makes waves..... it depends because you can have any amount and get different results any day though

hope this helps plz mark me brainliest

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Two objects, one with a mass of 2 m and one with a mass of 4 m are attracted to each other

Nadusha1986 [10]

It would be 7 M 4 m x 2 m equals 8 M - 1 =7

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2 years ago

When the tympanic membrane vibrates with the same frequency as the incoming sound waves it is known asamplitude.pitch.hertz.reso

Sphinxa [80]

<h2>Answer: Resonance </h2>

Resonance is a phenomenon that occurs when a body capable of vibrating is subjected to the action of a periodic force, whose frequency of vibration approaches the characteristic frequency of vibration (called resonance frequence) of said body. This is due a relatively small force applied in a repeated form, causing the amplitude of the oscillating system to become very large.

In other words, for the specific case of sound waves, this phenomenon occurs when the frequency of the wave that is external to the system or body coincides with the resonance frequency (characteristic frequency that reaches the maximum degree of oscillation) of this system or body.

In these circumstances the body vibrates, progressively increasing the amplitude of movement after each successive actions of the force. However, this effect can be destructive in some rigid materials.

4 0

3 years ago

describe what a person in the passenger seat will fill out the car ages poin describe what a person in the passenger seat will f

dedylja [7]

There are several possibilities. Here are a few that occur to me:

-- If Point-A is the summit of Pike's Peak, he may feel somewhat
short of breath.

-- If Point-A is his grandmother's house, he may feel a great sense
of pleasant anticipation.

-- If Point-A is his office on Monday morning, then he may feel
a tightening sensation in his chest.;

-- If Point-A is his home on Friday afternoon, then he feels the
effects of a slow and steady drop in his blood pressure.

I finer point might be put to it if we had any idea of where
Point-A is, and what it represents in the grand scheme
of things.

5 0

3 years ago

A 12 N force is used to pull a wagon 10 m to the left in 15 seconds. Which of the following represents the magnitude of the forc

Lana71 [14]

1. - 12N

2.- 2 hours

3. - 0.5 m/s/s

7 0

3 years ago

Read 2 more answers

(a) Consider the initial-value problem dA/dt = kA, A(0) = A0 as the model for the decay of a radioactive substance. Show that, i

murzikaleks [220]

Answer:

a) $t = -\frac{ln(2)}{k}$

b) See the proof below

$A(t) = A_o 2^{-\frac{t}{T}}$

c) $t = 3T \frac{ln(2)}{ln(2)}= 3T$

Explanation:

Part a

For this case we have the following differential equation:

$\frac{dA}{dt}= kA$

With the initial condition $A(0) = A_o$

We can rewrite the differential equation like this:

$\frac{dA}{A} =k dt$

And if we integrate both sides we got:

$ln |A|= kt + c_1$

Where $c_1$ is a constant. If we apply exponential for both sides we got:

$A = e^{kt} e^c = C e^{kt}$

Using the initial condition $A(0) = A_o$ we got:

$A_o = C$

So then our solution for the differential equation is given by:

$A(t) = A_o e^{kt}$

For the half life we know that we need to find the value of t for where we have $A(t) = \frac{1}{2} A_o$ if we use this condition we have:

$\frac{1}{2} A_o = A_o e^{kt}$

$\frac{1}{2} = e^{kt}$

Applying natural log we have this:

$ln (\frac{1}{2}) = kt$

And then the value of t would be:

$t = \frac{ln (1/2)}{k}$

And using the fact that $ln(1/2) = -ln(2)$ we have this:

$t = -\frac{ln(2)}{k}$

Part b

For this case we need to show that the solution on part a can be written as:

$A(t) = A_o 2^{-t/T}$

For this case we have the following model:

$A(t) = A_o e^{kt}$

If we replace the value of k obtained from part a we got:

$k = -\frac{ln(2)}{T}$

$A(t) = A_o e^{-\frac{ln(2)}{T} t}$

And we can rewrite this expression like this:

$A(t) = A_o e^{ln(2) (-\frac{t}{T})}$

And we can cancel the exponential with the natural log and we have this:

$A(t) = A_o 2^{-\frac{t}{T}}$

Part c

For this case we want to find the value of t when we have remaining $\frac{A_o}{8}$

So we can use the following equation:

$\frac{A_o}{8}= A_o 2^{-\frac{t}{T}}$

Simplifying we got:

$\frac{1}{8} = 2^{-\frac{t}{T}}$

We can apply natural log on both sides and we got:

$ln(\frac{1}{8}) = -\frac{t}{T} ln(2)$

And if we solve for t we got:

$t = T \frac{ln(8)}{ln(2)}$

We can rewrite this expression like this:

$t = T \frac{ln(2^3)}{ln(2)}$

Using properties of natural logs we got:

$t = 3T \frac{ln(2)}{ln(2)}= 3T$

8 0

3 years ago