Answer:
engineering that works on building structures.
Explanation:
Answer:
126984 cycles
Explanation:
Given data :
Sut = 530 MPa
f = 0.9
fully corrected Se = 210 MPa
using Miner's method attached below is the detailed solution of the given problem
when loaded with ± 225 MPa the number of cycles before it fails will be
≈ 126984
<u>Explanation:</u>
Let the frequency of the operation "W"ras/s

![\(\therefore\) Power, \(P(t)=v(t) I(t)\)$$\begin{array}{l}=[7.5 \cos \omega t][\cos (\cot -\pi / 6)] \times 10^{6} w \\=7.5 \cos ^{2}(2 \omega t-\pi / 6)+7.5 \cos \left(\pi_{6}\right) MW \\=3.75+7.5 \cos (2 \omega t-\pi / 6) \quad MW\end{array}$$](https://tex.z-dn.net/?f=%5C%28%5Ctherefore%5C%29%20Power%2C%20%5C%28P%28t%29%3Dv%28t%29%20I%28t%29%5C%29%24%24%5Cbegin%7Barray%7D%7Bl%7D%3D%5B7.5%20%5Ccos%20%5Comega%20t%5D%5B%5Ccos%20%28%5Ccot%20-%5Cpi%20%2F%206%29%5D%20%5Ctimes%2010%5E%7B6%7D%20w%20%5C%5C%3D7.5%20%5Ccos%20%5E%7B2%7D%282%20%5Comega%20t-%5Cpi%20%2F%206%29%2B7.5%20%5Ccos%20%5Cleft%28%5Cpi_%7B6%7D%5Cright%29%20MW%20%5C%5C%3D3.75%2B7.5%20%5Ccos%20%282%20%5Comega%20t-%5Cpi%20%2F%206%29%20%5Cquad%20MW%5Cend%7Barray%7D%24%24)

Answer: 
Explanation:
Given


Again differentiate for the second derivative

Answer:
it is to warn you about something like a dead end, or maybe where you should slow down because there might be people crossing ahead.
Explanation:
look at the signs i provided, all of them warn you about something.
Ex: railroad tracks, there might be a train passing, a winding road, so you don't go off road and crash, etc.