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xxTIMURxx [149]
3 years ago
10

What are two types of scientific investigations?

Physics
1 answer:
kvv77 [185]3 years ago
4 0
Experiments and fieldwork
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Referring to the above diagram, how high will the ball rise on the right-hand incline?
Marina CMI [18]
I think it’s 15cm
Might be 7cm
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4 years ago
How much work is done by the force of gravity when a 45 N object falls to the ground from a height of 4.6 m?
saul85 [17]
Work Done = 45N x 4.6m = 207J
5 0
3 years ago
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Calculate the potential energy of a 20-kg sled at 40 meters
irakobra [83]

Answer: 7840N

Explanation:

Given that

Potential energy = ?

Mass of sled = 20-kg

Distance = 40 meters

Acceleration due to gravity = 9.8m/s^2

Recall that potential energy is the energy possessed by a body at rest

i.e potential energy = mass m x acceleration due to gravity g x distance h

P.E = mgh

P.E = 20kg x 9.8m/s^2 x 40m

P.E = 7840N

Thus, the potential energy of the sled is 7840N

5 0
3 years ago
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Which of the following graph is used for determining the instantaneous velocity from the slope?
hoa [83]

Answer:

B. x - t graph

Explanation:

A position-time (x-t) graph is a graph of the position of an object against (versus) time.

Generally, the slope of the line of a position-time (x-t) graph is typically used to determine or calculate the velocity of an object.

An instantaneous velocity can be defined as the rate of change in position of an object in motion for a short-specified interval of time. Thus, an instantaneous velocity is a quantity that can be found by measuring the slope of a line that is tangent to a point on the graph.

Hence, the x - t graph also referred to as the position-time graph is used for determining the instantaneous velocity from the slope.

<u>For example;</u>

Given that the equation of motion is S(t) = 4t² + 2t + 10. Find the instantaneous velocity at t = 5 seconds.

Solution.

S(t) = 4t^{2} + 2t + 10

Differentiating the equation, we have;

S(t) = 8t + 2

Substituting the value of "t" into the equation, we have;

S(5) = 8(5) + 2

S(5) = 40 + 2

S(5) = 42 m/s.

5 0
3 years ago
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You are on a new planet, and are trying to use a simple pendulum to find the gravity experienced on this new planet. You find th
levacccp [35]

To solve this problem it is necessary to apply the concepts related to the Period based on the length of its rope and gravity, mathematically it can be expressed as

T= 2\pi \sqrt{\frac{L}{g}}

g = Gravity

L = Length

T = Period

Re-arrange to find the gravity we have

g = \frac{4\pi^2 L}{T^2}

Our values are given as

L = 0.35m\\T = 2s\\

Replacing we have

g = \frac{4\pi^2 L}{T^2}

g = \frac{4\pi^2 0.35}{2^2}

g = 3.45 m/s^2

Therefore the correct answer is C.

4 0
3 years ago
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