Answer:
The answer to your question is π = 12.47 atm
Explanation:
Data
mass of Magnesium citrate = 25.5 g
volume of solution = 244 ml
temperature = 37°C
molar mass C₆H₆MgO₇ = (12 x 6) + (1 x 6) + (24 x 1) + (16 x 7) = 214 g
Osmotic pressure = π = ?
Process
1.- Calculate the moles of magnesium citrate
214 grams ----------------- 1 mol
25.5 grams --------------- x
x = (25.5 x 1)/214
x = 0.119
2.- Calculate molarity
Molarity = moles/volume
Molarity = 0.119/0.244
Molarity = 0.49
3.- Calculate osmotic pressure
π = MRT
π = (0.49)(0.0821)(37 + 273)
π = (0.49)(0.0821)(310)
π = 12.47 atm
Answer:
the pressure of gas is 100.0 the volume is 500.0
Explanation:
Answer:
7,38 g of K₃PO₄
Explanation:
Molarity is an unit of chemical concentration. 0,139 M means 0,139 moles of solute per liter of solution.
In this case, the solute is potassium phosphate (K₃PO₄; molar mass: 212,27 g/mol) and the volume of the solution must be 250mL≡0,25L.
Thus, the moles of potassium phosphate you need are:
0,139 mol/L×0,25L = 0,03475 moles of K₃PO₄
In grams:
0,03475 moles of K₃PO₄ × 
= 7,38 g of K₃PO₄
I hope it helps!
That kilo-pascal is equivalent to 1678. 64 millimeters of mercury pressure
Because if they aren't properly included, it means that you are saying that the numbers can be anything, all reals.
Not including units is the same thing, if you don't properly lable the data table, you could be talking about anything.
Not giving a proper unit/variable is almost like giving someone permission to assume what you're talking about
