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Sidana [21]
3 years ago
10

A girl drops a pebble from a high cliff into a lake far below. She sees the splash of the pebble hitting the water 2.00s later.

How fast was the pebble going when it hit the water?
Physics
1 answer:
Natali5045456 [20]3 years ago
3 0

Answer:

19.62 ms

Explanation:

t = Time taken = 2 s

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s² (downward direction is taken as positive)

Equation of motion

v=u+at\\\Rightarrow v=0+9.81\times 2\\\Rightarrow v=19.62\ m/s

The speed of the pebble when it hit the water is 19.62 ms

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3 years ago
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Two boxes (24 kg and 62 kg) are being pushed across a horizontal frictionless surface, as the drawing shows. The 36-N pushing fo
defon

Answer:

F = 26.04 N

Explanation:

As we know that system of two boxes are moving on frictionless surface

So here if two boxes are considered as a system

then we have

F = (m_1 + m_2) a

m_1 = 24 kg

m_2 = 62 kg

F = 36 N

36 = (24 + 62) a

a = 0.42 m/s^2

Now since we know that both the boxes are moving together so force applied by first box on other box is given as

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F = (62 \times 0.42)

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6 0
3 years ago
If gravity between the Sun and Earth suddenly vanished, Earth would continue moving in
Ksenya-84 [330]

Answer:

Earth would continue moving by uniform motion, with constant velocity, in a straight line

Explanation:

The question can be answered by using Newton's first law of motion, also known as law of inertia, which states that:

"an object keeps its state of rest or of uniform motion in a straight line unless acted upon by an external net force different from zero"

This means that if there are no forces acting on an object, the object stays at rest (if it was not moving previously) or it continues moving with same velocity (if it was already moving) in a straight line.

In this problem, the Earth is initially moving around the Sun, with a certain tangential velocity v. When the Sun disappears, the force of gravity that was keeping the Earth in circular motion disappears too: therefore, there are no more forces acting on the Earth, and so by the 1st law of Newton, the Earth will continue moving with same velocity v in a straight line.

6 0
3 years ago
A ball is thrown straight up with enough speed so that it is in the air for several seconds. Assume the positive direction is up
Andrew [12]

Answer:

a) v= 0 m/s b) v= 6.86 m/s

Explanation:

a) When the ball reaches to its highest point, under the influence of gravity, before starting to fall down, it momentarily comes to an stop (this is needed prior to change direction in any movement), so, applying the definition of acceleration, and replacing the acceleration a by g, we have:

vf = v₀ - g*t (1)

The minus sign means that the acceleration due to gravity is always downward, so if we assume that the positive direction is upwards it must be negative.

At the highest point, vf= 0.

b) Prior to solve this point, we need to know which is the time when the ball reaches to its highest point.

As we know vf=0, we can solve (1) for t, as follows:

th = v₀/g

Now, for a time that is 0.7 s before this time, applying the acceleration definition and solving for v again, we have:

v = v₀ -(g *(th-0.7 s)), but th= v₀/g, so we get:

v= v₀ -g((v₀/g)-0.7 s) = v₀ - v₀ + g*0.7 s

⇒ v=g*0.7 s = 9.8 m/s²*0.7 s

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6 0
3 years ago
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Answer:

X: Use DC

Y: Use AC

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