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Karo-lina-s [1.5K]
4 years ago
14

Two racecars are driving at constant speeds around a circular track. Both cars are the same distance away from the center of the

track, but car 2 is driving twice as fast as car 1. The acceleration of car 2 is ___________ the acceleration of car 1. Two racecars are driving at constant speeds around a circular track. Both cars are the same distance away from the center of the track, but car 2 is driving twice as fast as car 1. The acceleration of car 2 is ___________ the acceleration of car 1. twice half of equal to four times a quarter of
Physics
1 answer:
Alenkasestr [34]4 years ago
4 0

Answer:

The acceleration of car 2 is four times of the acceleration of car 1.

Explanation:

The centripetal acceleration of the object is possessed when it moves in a circular path. It is given by :

a=\dfrac{v^2}{r}

In this case, two race cars are driving at constant speeds around a circular track. Both cars are the same distance away from the center of the track, but car 2 is driving twice as fast as car 1.

So,

\dfrac{a_1}{a_2}=\dfrac{v_1^2}{v_2^2}

1 and 2 represent car 1 and car 2 respectively.

v_2=2v_1

So,

\dfrac{a_1}{a_2}=\dfrac{v_1^2}{(2v_1)^2}\\\\\dfrac{a_1}{a_2}=\dfrac{v_1^2}{4v_1^2}\\\\\dfrac{a_1}{a_2}=\dfrac{1}{4}\\\\a_2=4\times a_1

So, the acceleration of car 2 is four times of the acceleration of car 1.

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A swimmer takes 45 seconds to complete a 100-meter lap. Calculate the swimmer’s average speed.
g100num [7]
2.22 m/s. Average speed is Total distance over time it took. 100m/45s = 2.22m/s
5 0
3 years ago
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A balloon filled with helium gas has an average density of rhob = 0.22 kg/m3. The density of the air is about rhoa = 1.23 kg/m3.
MissTica

Answer:

a=g\left(\frac{\rho_a}{\rho_b}-1\right)

45.03681 m/s²

Explanation:

F_b = Buoyant force

W = Weight of the balloon

\rho_a = Density of air = 1.23 kg/m³

\rho_b = Density of balloon = 0.22 kg/m³

v_a = Volume of air

v_b = Volume of balloon

F_b=\rho_av_bg

W=\rho_bv_bg

g = Acceleration due to gravity = 9.81 m/s²

The net force acting on the balloon is

F=F_b-W\\\Rightarrow F=\rho_av_bg-\rho_bv_bg\\\Rightarrow \rho_bv_ba=\rho_av_bg-\rho_bv_bg\\\Rightarrow \rho_bv_ba=v_bg(\rho_a-\rho_b)\\\Rightarrow a=\frac{g}{\rho_b}(\rho_a-\rho_b)\\\Rightarrow a=g\left(\frac{\rho_a}{\rho_b}-1\right)

The equation is a=g\left(\frac{\rho_a}{\rho_b}-1\right)

a=g\left(\frac{\rho_a}{\rho_b}-1\right)\\\Rightarrow a=9.81\times \left(\frac{1.23}{0.22}-1\right)\\\Rightarrow a=45.03681\ m/s^2

The acceleration of the balloon is 45.03681 m/s²

8 0
3 years ago
A charged particle is accelerated in a uniform electric field. When its velocity is 2 m/s, its electric potential energy is 100
zavuch27 [327]

Answer:

particle's potential energy = 70J

Explanation:

From conservation of energy; K1 + Ue1 = K2 + Ue2

where K1 and K2 are the kinetic energies at two positions and Ue1 and Uue2 are the electrical potential energies at two positions.

k1 = 10J, Ue1 = 100J

K2 = 40J

substitute into K1 + Ue1 = K2 + Ue2

Ue2 = K1 + Ue1 - K2

= 10 +100 - 40

Ue2 = 70J

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3 years ago
Consider a turnbuckle that has been tightened until the tension in wire AD is 350 N. Draw the FBD that is required to determine
Mars2501 [29]

Answer:

yes

Explanation:

yes

6 0
3 years ago
On April 15, 1999, a South Korean cargo plane crashed due to a confusion over units. The plane was to fly from Shanghai, China,
sattari [20]

Answer:

993 m or 3257 ft

Explanation:

The captain was told to fly at at 1500 ft altitude. At the rate of 3.28 ft to 1 m, this is

\dfrac{1500}{3.28}=457 metres.

Since he was at 1450 m, he thought he was above the correct altitude by

1450 - 457 = 993 m.

In feet, this is

993 * 3.28 = 3257 ft

6 0
3 years ago
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