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Karo-lina-s [1.5K]
3 years ago
14

Two racecars are driving at constant speeds around a circular track. Both cars are the same distance away from the center of the

track, but car 2 is driving twice as fast as car 1. The acceleration of car 2 is ___________ the acceleration of car 1. Two racecars are driving at constant speeds around a circular track. Both cars are the same distance away from the center of the track, but car 2 is driving twice as fast as car 1. The acceleration of car 2 is ___________ the acceleration of car 1. twice half of equal to four times a quarter of
Physics
1 answer:
Alenkasestr [34]3 years ago
4 0

Answer:

The acceleration of car 2 is four times of the acceleration of car 1.

Explanation:

The centripetal acceleration of the object is possessed when it moves in a circular path. It is given by :

a=\dfrac{v^2}{r}

In this case, two race cars are driving at constant speeds around a circular track. Both cars are the same distance away from the center of the track, but car 2 is driving twice as fast as car 1.

So,

\dfrac{a_1}{a_2}=\dfrac{v_1^2}{v_2^2}

1 and 2 represent car 1 and car 2 respectively.

v_2=2v_1

So,

\dfrac{a_1}{a_2}=\dfrac{v_1^2}{(2v_1)^2}\\\\\dfrac{a_1}{a_2}=\dfrac{v_1^2}{4v_1^2}\\\\\dfrac{a_1}{a_2}=\dfrac{1}{4}\\\\a_2=4\times a_1

So, the acceleration of car 2 is four times of the acceleration of car 1.

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You collect some more data on that horse at a later time interval, but now you are measuring thehorse’s velocity, not its positi
Monica [59]

Answer:

a)  x(t) = 10t + (2/3)*t^3

b) x*(0.1875) = 10.18 m

Explanation:

Note: The position of the horse is x = 2m. There is a typing error in the question. Otherwise, The solution to cubic equation holds a negative value of time t.

Given:

- v(t) = 10 + 2*t^2 (radar gun)

- x*(t) = 10 + 5t^2 + 3t^3  (our coordinate)

Find:

-The position x of horse as a function of time t in radar system.

-The position of the horse at x = 2m in our coordinate system

Solution:

- The position of horse according to radar gun:

                              v(t) = dx / dt = 10 + 2*t^2

- Separate variables:

                              dx = (10 + 2*t^2).dt

- Integrate over interval x = 0 @ t= 0

                             x(t) = 10t + (2/3)*t^3

- time @ x = 2 :

                              2 = 10t + (2/3)*t^3

                              0 = 10t + (2/3)*t^3 + 2

- solve for t:

                              t = 0.1875 s

- Evaluate x* at t = 0.1875 s

                              x*(0.1875) = 10 + 5(0.1875)^2 + 3(0.1875)^3

                              x*(0.1875) = 10.18 m

3 0
3 years ago
You are a crane operator using a wrecking ball to demolish an old building. You can choose to use a 100-kg ball or a 150-kg ball
Elenna [48]

Answer:

The answer to the question is

The two balls, although of different masses, could be made to have the same demolishing force by setting the velocity of the 100 kg ball to 1.5 times the velocity of the 150 kg ball.

That is if V₁ is the velocity of the 150 kg ball and  V₂ is the velocity of the 100 kg ball then V₂  = 1.5×V₁ for the demolishing effect of the two balls to be equal.

Explanation:

To answer the we are required to explain the meaning of momentum and state its properties

Momentum is a physical property of an object in motion. It indicates the amount of motion inherent in the object.  An object in motion is said to have momentum

The types of momentum possessed by an object can be classified into either

1, Linear momentum or

2. Angular momentum

An object moving with a velocity, v has linear momentum while a spinning object has an angular momentum

The momentum is given by the formula

P = m × V

Where m = mass and

V = velocity

Newtons second law of motion states that, the force acting on an object is equivalent to the rate of change of momentum produced and acting in the direction of the force

Properties of momentum

From the above statements it means that the two balls can be made equivalent by having the appropriate amount of speed. That iis the two balls can have the same momentum thus for equal momentum effect, we have

150 kg × V₁ = 100 kg × V₂

or V₂ = 1.5×V₁

3 0
3 years ago
An object is originally moving at a constant velocity of 8 m/s in the -x direction. It moves at this constant velocity for 3 sec
aivan3 [116]

Answer:

244.64m

Explanation:

First, we find the distance traveled with constant velocity. It's simply multiplying velocity time the time that elapsed:

x = V*t = -8\frac{m}{s} *3s = -24m

After this, the ball will start traveling with a constant acceleration motion. Due to the fact that the acceleration is the opposite direction to the initial velocity, this motion will have 2 phases:

1. The velocity will start to decrease untill it reaches 0m/s.

2. Then, the velocity will start to increase at the rate of the acceleration.

The distance that the ball travels in the first phase can be found with the following expression:

v^2 = v_0^2 + 2a*d

Where v is the final velocity (0m/s), v_0 is the initial velocity (-8m/s) and a is the acceleration (+9m/s^2). We solve for d:

d = \frac{v^2 - v_0^2}{2a} = \frac{(0m/s)^2 - (-8m/s)^2}{2*7m/s^2}= -4.57m

Now, before finding the distance traveled in the second phase, we need to find the time that took for the velocity to reach 0:

t_1 = \frac{v}{a} = \frac{8m/s}{7m/s^2} = 1.143 s

Then, the time of the second phase will be:

t_2 = 9s - t_1 = 9s - 1.143s = 7.857s

Using this, we using the equations for constant acceleration motion in order to calculate the distance traveled in the second phase:

x = \frac{1}{2}a*t^2 + v_0*t + x_0

V_0, the initial velocity of the second phase, will be 0 as previously mentioned. X_0, the initial position, will be 0, for simplicity:

x = \frac{1}{2}*7\frac{m}{s^2}*t^2 + 0m/s*t + 0m = 216.07m

So, the total distance covered by this object in meters will be the sum of all the distances we found:

x_total = 24m + 4.57m + 216.07m = 244.64m

8 0
2 years ago
The ____ is the place where position equals zero
Alexus [3.1K]
The answer to your question is the Origin 
7 0
3 years ago
Use the drop-down menus to identify the type of energy each phrase describes.
Tresset [83]

The shortest wavelength of visible light = violet light

Energy that can be felt as heat but not seen = infrared

Short, invisible rays that can cause eye damage = ultraviolet

Visible light with the longest wavelength = red light

Explanation:

Electromagnetic waves are waves consisting of oscillations of the electric and the magnetic field, occurring in a plane perpendicular to the direction of motion the wave.

They are the only type of waves able to travel without a medium, and they are transverse in nature.

All electromagnetic waves travel in a vacuum at the speed of light, which value is:

c=3.0\cdot 10^8 m/s

Electromagnetic waves are classified into 7 different classes, depending on their wavelength/frequency, and they have different properties. From shortest to longest wavelength (and from highest to lowest frequency), they are:

Gamma rays

X rays

Ultraviolet

Visible light

Infrared radiation

Microwaves

Radio waves

Moreover, the visible light of the spectrum is further divided into different colors, according to how our eye perceive them; from shortest to longest wavelength:

violet

blue

green

yellow

orange

red

Therefore, we have:

  • The shortest wavelength of visible light is violet light, which has wavelength between 380 and 450 nm
  • The longest wavelength of visible light is red light, which has wavelenght between 620 and 750 nm
  • Infrared radiation is a type of radiation that is felt as heat by our body, however it cannot be seen because it falls outside the spectrum of visible light
  • Ultraviolet radiation is also invisible to human eye; it has shorter wavelength than visible light and therefore it has more frequency (and more energy), therefore it can cause damage, especially to the eye

Learn more about electromagnetic waves:

brainly.com/question/9184100

brainly.com/question/12450147

#LearnwithBrainly

5 0
3 years ago
Read 2 more answers
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