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wariber [46]
3 years ago
6

Sorry I keep asking questions, but if two forces on an object are balanced, will it move? (Im also trying to get rid of my point

s) XD
Physics
2 answers:
Dmitrij [34]3 years ago
6 0
If they are equal amounts in force then No it won't.
muminat3 years ago
4 0
If the two forces are acting on the object in opposite directions(ex: push from the back and a push from the front), the object will not move.
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28.65m x 15.24m

Explanation:

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3 years ago
Consider a sound wave moving through the air modeled with the equation s(x, t) = 5.00 nm cos(60.00 m−1x − 18.00 ✕ 103 s−1t). Wha
GaryK [48]

Answer:

Shortest time = 58.18 × 10^(-6) s

Explanation:

We are given;

s(x,t) = 5.00 nm cos((60.00 m^(−1)x) − (18.00 X 10³ s^(−1)t))

Let us set x = 0 as origin.

Now, for us to find the time difference, we need to solve 2 equations which are;

s(x,t) = 5.00 nm cos((60.00 m^(−1)x) − (18.00 X 10³ s^(−1)t1))

And

s(x,t) = 5.00 nm cos((60.00 m^(−1)x) − (18.00 X 10³ s^(−1)t2))

Now, since the wave starts from maxima at time at t = 0, the required time would be the difference (t2 - t1)

Thus, the solutions are;

t1 = (1/(18 × 10³)) cos^(-1) (2.5/5)

And

t2 = (1/(18 × 10³)) cos^(-1) (-2.5/5)

Angle of the cos function is in radians, thus;

t1 = 58.18 × 10^(-6) s

t2 = 116.36 × 10^(-6) s

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Required time = t2 - t1 = (116.36 × 10^(-6) s) - (58.18 × 10^(-6) s) = 58.18 × 10^(-6) s

4 0
3 years ago
Find the velocity of a dropped brick after 5.0 s using v =a ∆ t and a = - 9.8 m/s^2
Verizon [17]

Answer:

49

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8 0
3 years ago
Question # 40
jenyasd209 [6]

Answer:

Potential Energy = x = m g h

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