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3 years ago

12

WIL MARK U AS BRAINLIEST HELP PLZ

1 answer:

ss7ja [257]3 years ago

4 0

Answer:

The 1st one:Your natural ability

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the coil polarity in a waste spark system is determined by the direction in which the coil is wound (left hand rule for conventi

zaharov [31]

The coil polarity in a waste-spark system is determined by the direction in which the coil is wound (left-hand rule for conventional current flow)and can’t be changed. For example, if a V-8 engine has a firing order of 18436572 and the number 1 cylinder is on compression, which cylinder will be on the exhaust stroke?

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2 years ago

What is the average distance (in terms of R) between the mobile on the fringe of the serving cell and the second and third tier

kramer

Answer:

do you need all work shown for this?

4 0

3 years ago

The time to failure for a gasket follows the Weibull distribution with ß = 2.0 and a characteristic life of 300 days. What is th

Aleks04 [339]

Answer:

64.11% for 200 days.

t=67.74 days for R=95%.

t=97.2 days for R=90%.

Explanation:

Given that

β=2

Characteristics life(scale parameter α)=300 days

We know that Reliability function for Weibull distribution is given as follows

$R(t)=e^{-\left(\dfrac{t}{\alpha}\right)^\beta}$

Given that t= 200 days

$R(200)=e^{-\left(\dfrac{200}{300}\right)^2}$

R(200)=0.6411

So the reliability at 200 days 64.11%.

When R=95 %

$0.95=e^{-\left(\dfrac{t}{300}\right)^2}$

by solving above equation t=67.74 days

When R=90 %

$0.90=e^{-\left(\dfrac{t}{300}\right)^2}$

by solving above equation t=97.2 days

7 0

3 years ago

Which of the following processes is similar to the problem-solving process?

alina1380 [7]

Answer:

The engineering design process

Explanation:

6 0

3 years ago

A mass of 7 kg undergoes a process during which there is heat transler frorn the mass at a rate of 2 kJ per kg, an elevation dec

irinina [24]

Answer:44.61 KJ

Explanation:

Let h_1,V_1,Z_1 be the initial specific enthalpy,velocity&elevation of the system

and h_2,V_2,Z_2 be the Final specific enthalpy,velocity&elevation of the system

mass(m)=7kg

Applying Steady Flow Energy Equation

$m\left [ h_1+\frac{v_1^2}{2g}+gZ_1\right ]$ +Q= $\left [ h_2+\frac{v_2^2}{2g}+gZ_2\right ]$ +W

$h_1-h_2=4 KJ/kg$

$V_1=13m/s$

$V_2=23m/s$

$Z_1-Z_2=40m$

substituting values

$7\left [ h_1+\frac{13^{2}}{2g}+gZ_1\right ]+7\times2$ = $\left [ h_2+\frac{23^2}{2g}+gZ_2\right ]$ +W

W= $7\left [h_1-h_2+\frac{V_1^2-V_2^2}{2000g}+g\frac{\left (Z_1-Z_2 \right )}{1000}\right ]$ +Q

W= $7\left [4+\frac{13^2-23^2}{2000g}+g\frac{\left (40 \right )}{1000}[\right ]$ + $2\times 7$

W=44.61KJ

4 0

3 years ago