Answer:
Length = 2.453 m
Explanation:
Given:
Resistivity of the wire (ρ) = 1 × 10⁻⁶ Ω-m
Diameter of the wire (d) = 0.250 mm = 0.250 × 10⁻³ m
Resistance of the wire (R) = 50 Ω
Length of the wire (L) = ?
The area of cross section is given as:

We know that, for a constant temperature, the resistance of a wire is directly proportional to its length and inversely proportional to its area of cross section. The constant of proportionality is called the resistivity of the wire. Therefore,

Expressing the above in terms of length 'L', we get:

Plug in the given values and solve for 'L'. This gives,

Therefore, length of No. 30 wire (of diameter 0.250 mm) is 2.453 m.
It's important because first, we might be able to understand further with how gravity works. And if we can harness the power that black hole possesses, which pulls everything in, then we might be able to use that power for a huge amount of energy, thus possibly replacing solar energy, fossil fuels, etc.,.
Answer:
The required steady force of each rocket is 28.79 N
Explanation:
mass of the satellite, M=3900 kg
radius, r=4.3 m
mass of rocket, m=210 kg
time, t=5.4 min
Moment of Inertia:
I = 1/2 (Mr^2) + 4mr^2
I = 1/2 ( 3900* (4.3)^2) + 4 (210)*(4.3)^2
I = 51587.1 kg m^2
the angular acceleration is:
a= w/t
here w= 2*π*30
so,
a= 2*π*30 / 5.4* 3600
a=0.0096 rad/ s^2
the Torque becomes:
T=I*a = 4r*F
( 51587.1 )*(0.0096) = 4*4.3* F
F= 28.79 N
the required steady force of each rocket is 28.79 N
learn more about steady force here:
<u>brainly.com/question/13841147</u>
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