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2 years ago

Compare the mass of the ice cube with the mass of water vapor pleaseeee help

1 answer:

5 0

Hmmm Yes ice does have the same mass as water before it melts. You can (almost) never lose or gain mass without adding or subracting mass from the system. Mass just can't appear or dissappear from nowehere. <span>
It is known as the law of conservation of mass.

In water though, the volume that ice occupies is greater than that of water due to the arrangements of the molecules of ice. This is why you would be led to think ther is a change in mass.

A good weigh to prove this to yourself would be to get an ice cube in a bowl and place it on a set of scales as it melts. You shouldn't notice any real mass change.

p.s. my almost never is because that nuclear reactions can turn mass into energy through Einsteins equation E=mc2 but that is rare,</span><span>
</span>

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A $100 cart is moving down an inclined plane at 1.30 m/s. The cart collides with a stationary object and rebounds with a speed o

Rasek [7]

Answer:

0.65 kg*m/s and 0.165 kg*m/s

Explanation:

Step one:

given data

mass m= 0.5kg

initial velolcity u=1.3m/s

final velocity v= 0.97m/s

Required

The change in momentum

Step two:

We know that the expression for impulse is given as

Ft= mv

Ft= 0.5*1.3

Ft= 0.65 kg*m/s

The expression for the change in momentum is given as

P= mΔv

substitute

Pt= 0.5*(1.3-0.97)

Pt= 0.5*0.33

Pt=0.165 kg*m/s

7 0

2 years ago

While traveling home at dusk, a motorcyclist gets on the highway and increases the combined mass (400 kg

alexdok [17]

The acceleration of one of those bugs is equal to 305mi/s.

<h3>Acceleration calculation</h3>

To calculate the insect's acceleration, the action and reaction force of the impact must be considered.

As the insect will hit the helmet, the force it hits is the same force it receives, so we can make the following expression:

$m_m \times a_m = m_b \times a_b$

$550 \times 0.0027 = 5 \times 10^{-3} \times a_b$

<em>Speed has been converted to miles per second</em>

$a_b = 305 mi/s$

So, the acceleration of one of those bugs is equal to 305mi/s.

Learn more about acceleration calculation: brainly.com/question/390784

8 0

1 year ago

A mass of 1 kg is moving in a circle of radius 3.3 meters. What is the liner velocity v m/s that would give a Centripetal Force

Ghella [55]

Answer:

The linear velocity of the object is 8.71 m/s.

Explanation:

Given;

mass of the object, m = 1 kg

radius of the circle, r = 3.3 meters

centripetal force, F = 23 N

Centripetal force is given by;

$F_c = \frac{mv^2}{r}\\\\$

where;

v is the linear velocity of the object

$F_c = \frac{mv^2}{r}\\\\mv^2 = F_cr\\\\v^2 = \frac{F_cr}{m}\\\\v= \sqrt{\frac{F_cr}{m}} \\\\v= \sqrt{\frac{23*3.3}{1}}\\\\v = 8.71 \ m/s$

Therefore, the linear velocity of the object is 8.71 m/s.

4 0

3 years ago

Centrifugal force increases with

belka [17]

Centrifugal force is not a real force.

When you move around a curve, there IS a real force pulling you
around the curve. Since your body wants to go straight, it feels as if
there's a force trying to pull you away from the curve. But there isn't.

That feeling of a force is greater when your speed around the curve
is greater, or when the curve is tighter, i.e. smaller radius.

8 0

2 years ago

Read 2 more answers

Coulomb’s law is similar to what other law in physics?

Gemiola [76]

Universal law of gravitation

6 0

2 years ago

Read 2 more answers