Answer:
False
Explanation:
The torque exerted by a force is given by:
where
F is the magnitude of the force
d is the distance between the point of application of the force and the pivot
is the angle between the directions of F and d
We see that the magnitude of the torque depends on 3 factors. In this problem, we have 2 forces of equal magnitude (so, equal F). Moreover, one of the forces (let's call it force 1) acts farther from the pivot than force 2, so we have
However, this does not mean that force 1 produces a greater torque. In fact, it also depends on the angle at which the force is applied. For instance, if the first force is applied parallel to d, then we have
and the torque produced by this force would be zero.
So, the statement is false.
We know that,
- Force = mass× acceleration
We already have mass so let us calculate accleration experienced by it, using first equation of motion;
- v = u + at
- 1.55 = 0 + a(3)
- 1.55 = 3a
- 1.55/3 = a
- 0.51 m/s² = a
Put this in force's formula;
- f = ma
- f = 600 × 0.51
- f = 306.00
- f = 306 N
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Answer:
a) The magnitude of the car's total displacement (T) from the starting point is T = 82.67 Km
b) The angle (θ) from east of the car's total displacement measured from the starting direction is θ = 40.88 °
Explanation:
Attached you can see a diagram of the problem.
a) Find the magnitude of the vector T that goes from point A to point D (see the diagram).
The x and y components of this vector are
The magnitude of the vector is find using the pythagoras theorem:
, being a, b and c the 3 sides of the triagle that forms the vector:
Replacing the values
b) Find the angle θ that forms the vector T and the vector AB (see diagram).
To find this angle you can use the inverse tangent
θ
θ
θ=40.88°