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scoray [572]
3 years ago
8

The line that is drawn perpendicular to the point at which a wave intersects a boundary is known as the _____.

Physics
1 answer:
MAVERICK [17]3 years ago
3 0
<span>The line that is drawn perpendicular to the point at which a wave intersects a boundary is known as the normal.</span>
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2. Before 0.5-kg ball is dropped from a third story window 20 m above the sidewalk. What is the potential
Flauer [41]

Answer:

C

Explanation:

C

20*9.8*0.5

98

4 0
3 years ago
Read 2 more answers
The weight of a girl with the mass of 40.0kg is ?
Allushta [10]

Answer:

392 Newtons

Explanation:

In order to find the weight, you have to multiply the mass by the gravitation constant (9.8), which gives us 40.0 * 9.8 = 392 Newtons.

4 0
3 years ago
A mass of 2 kg is attached to a spring and placed on a horizontal surface. The spring has a spring constant of 20 N/m, and the s
Sergio [31]

The speed of the mass : <em><u>v = 0.316 m/s</u></em>

<h3>Further explanation</h3>

The energy used to press a spring is included as the potential energy

Can be formulated:

\displaystyle E_p=\frac{1}{2}kx^2

Ep= potential energy

k = spring constant

x = change in spring length

If the spring is released from its pressure, this potential energy will turn into kinetic energy

so applies the law of conservation of mechanical energy (Em)

Ek = Ep

A mass of 2 kg is attached to a spring, a spring constant of 20 N/m, and the spring is compressed 0.1 m past its natural length.

m = 2 kg

k = 20 N/m

x = 0.1 m

\displaystyle Ep=Ek\\\\\frac{1}{2}kx^2=\frac{1}{2}mv^2\\\\kx^2=mv^2\\\\20\times0.1^2=2\times v^2\\\\v^2=0.1\\\\v=\sqrt{0.1}\\\\v=0.316~m/s

<h3>Learn more</h3>

Hooke's law

brainly.com/question/2648431

Keywords : spring,mass, spring constant,compressed position

5 0
4 years ago
A car travels 10.0 m/s. What is its velocity in km/h?
Vitek1552 [10]
Since 1m/s=3.6 km/h, we can conclude that 10.0m/s = 36 km/h
5 0
3 years ago
A 1500kg car is at rest before it accelerates when the light turns green. If it covers 45.0 meters in 15.0 seconds, what is the
lana [24]

Answer:

300N

Explanation:

Given parameters:

Mass of car  = 1500kg

Initial velocity  = 0m/s

Distance covered  = 45m

Time  = 15s

Unknown:

Net force applied  = ?

Solution:

From Newton's second law:

  Force  = mass x acceleration

  Force  = mass x \frac{v - u}{t}  

v is the final velocity

u is the initial velocity

t is the time taken

    Final velocity  = \frac{45}{15}   =3m/s

 Force  = 1500 x \frac{3 - 0}{15}   = 300N

8 0
3 years ago
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