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3 years ago

How many carbon atoms C3H8 has 3.92 X 10^24 H atoms

Chemistry

1 answer:

Alchen [17]3 years ago

5 0

Answer:

There would be 1.47 x 10^24 carbon atoms in the sample.

Explanation:

If I've understoof the question, you mean you have a sample of C3H8 that contains 3.92 x 10^24 H atoms and want to know how many carbon atoms there are in that sample.

You can figure that out using the ratio of C atoms to H atoms, 3:8.

3.92 x 10^24 H atoms x 3 C atoms/8 H atoms = 1.47 x 10^24 C atoms

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What are “condensation nuclei”?

Kruka [31]

Answer:

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2 years ago

Calculate ∆G ◦ r for the decomposition of mercury(II) oxide 2 HgO(s) → 2 Hg(ℓ) + O2(g) ∆H◦ f −90.83 − − (kJ · mol−1 ) ∆S ◦ m 70.

bagirrra123 [75]

Answer:

4. +117,1 kJ/mol

Explanation:

ΔG of a reaction is:

ΔGr = ΔHr - TΔSr (1)

For the reaction:

2 HgO(s) → 2 Hg(l) + O₂(g)

ΔHr: 2ΔHf Hg(l) + ΔHf O₂(g) - 2ΔHf HgO(s)

As ΔHf of Hg(l) and ΔHf O₂(g) are 0:

ΔHr: - 2ΔHf HgO(s) = 181,66 kJ/mol

In the same way ΔSr is:

ΔSr= 2ΔS° Hg(l) + ΔS° O₂(g) - 2ΔS° HgO(s)

ΔSr= 2* 76,02J/Kmol + 205,14 J/Kmol - 2*70,19 J/Kmol

ΔSr= 216,8 J/Kmol = 0,216 kJ/Kmol

Thus, ΔGr at 298K is:

ΔGr = 181,66 kJ/mol - 298K*0,216kJ/Kmol

ΔGr = +117,3 kJ/mol ≈ 4. +117,1 kJ/mol

I hope it helps!

5 0

3 years ago

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3 years ago

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3 years ago

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Explanation:I had to take this on a test.

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2 years ago