Answer:
1.08 s
Explanation:
From the question given above, the following data were obtained:
Height (h) reached = 1.45 m
Time of flight (T) =?
Next, we shall determine the time taken for the kangaroo to return from the height of 1.45 m. This can be obtained as follow:
Height (h) = 1.45 m
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =?
h = ½gt²
1.45 = ½ × 9.8 × t²
1.45 = 4.9 × t²
Divide both side by 4.9
t² = 1.45/4.9
Take the square root of both side
t = √(1.45/4.9)
t = 0.54 s
Note: the time taken to fall from the height(1.45m) is the same as the time taken for the kangaroo to get to the height(1.45 m).
Finally, we shall determine the total time spent by the kangaroo before returning to the earth. This can be obtained as follow:
Time (t) taken to reach the height = 0.54 s
Time of flight (T) =?
T = 2t
T = 2 × 0.54
T = 1.08 s
Therefore, it will take the kangaroo 1.08 s to return to the earth.
Answer:
The reading will be the same.
Explanation:
Mass does not depend upon anything and it remains the same anywhere. What changes is the weight of the body because it depends upon gravity and is different at different places.
Giving me the brainest will be helpful.
B.) should be the right/best answer if u divided
Answer:
65.9°
Explanation:
When light goes through air to glass
angle of incidence, i = 35°
refractive index, n = 1.5
Let r be the angle of refraction
Use Snell's law
Sin r = 0.382
r = 22.5°
Now the ray is incident on the glass surface.
A = r + r'
Where, r' be the angle of incidence at other surface
r' = 60° - 22.5° = 37.5°
Now use Snell's law at other surface
Where, i' be the angle at which the light exit from other surface.
Sin i' = 0.913
i' = 65.9°
