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olasank [31]
3 years ago
12

Martino travels from her house to her moms office building from there she walks to school after school she walks to the library

and then to a friends house before finally ending back at home find Martinez total displacement?
A) 0 miles
B) 0.4 miles
C) 1 mile
D) 3.15 miles

Physics
2 answers:
Jlenok [28]3 years ago
4 0

Answer:

A) 0 miles

Explanation:

The displacement is the distance between the starting point and the end point of the route.

In this case, even if Matino takes a whole tour around the city, since<u> it ends in the same place where it started</u>, the difference between the starting and finishing point is zero, so its total displacement is zero.

Care must be taken to distinguish the terms of displacement and distance traveled, beacause they are not the same, since in this case the distance traveled would be 3.15miles, but the displacement is zero, because it ends at the point where it started.

Ray Of Light [21]3 years ago
3 0

Answer:

D) 3.15 miles

Explanation:

The total distance travelled is 3.15 miles. Distance is found simply by adding up all the individual parts. The displacement would be 0.

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I didn't hear about "waves adding" before..so i guess 1st statement is right.

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2 years ago
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The deck of a bridge is suspended 235 feet above a river. If a pebble falls off the side of the bridge, the height, in feet, of
Aleks04 [339]

Answer:

(a) 1, average velocity = -65.6 m/s

   2, average velocity = -64.8 m/s

   3, average velocity = -64.16 m/s

(b) The instantaneous velocity is -96 m/s

Explanation:

(a)

Average velocity is given  by;

y(t_2,t_1) = \frac{y(t_2) - y(t_1)}{t_2-t_1}

(1)

y(2.1,2) = \frac{(235-16*2.1^2) - (235-16*2^2)}{2.1-2}\\\\ y(2.1,2) = -65.6 \ m/s

(2)

y(2.05,2) = \frac{(235-16*2.05^2) - (235-16*2^2)}{2.05-2}\\\\ y(2.05,2) = -64.8 \ m/s

(3)

y(2.01,2) = \frac{(235-16*2.01^2) - (235-16*2^2)}{2.01-2}\\\\ y(2.01,2) = -64.16 \ m/s

b. y = 235 - 16t²

The instantaneous velocity is given by;

v = dy /dt

dy / dt = -32t

when t = 3 s

v = -32(3)

v = -96 m/s

5 0
3 years ago
A parallel-plate capacitor has plates of area A. The plates are initially separated by a distance d, but this distance can be va
ohaa [14]

Answer:

d' = d /2

Explanation:

Given that

Distance = d

Voltage =V

We know that energy in capacitor given as

U=\dfrac{1}{2}CV^2

C=\dfrac{\varepsilon _oA}{d}

U=\dfrac{1}{2}\times \dfrac{\varepsilon _oA}{d}\times V^2

If energy become double U' = 2 U then d'

U'=\dfrac{1}{2}\times \dfrac{\varepsilon _oA}{d'}\times V^2

2U=\dfrac{1}{2}\times \dfrac{\varepsilon _oA}{d'}\times V^2

2\times \dfrac{1}{2}\times \dfrac{\varepsilon _oA}{d}\times V^2=\dfrac{1}{2}\times \dfrac{\varepsilon _oA}{d'}\times V^2

2 d ' = d

d' = d /2

So the distance between plates will be half on initial distance.

7 0
3 years ago
The critical angle for total internal reflection for cubic zirconia surrounded by air is 27.0°. Calculate the polarizing angle f
Anna11 [10]

Answer:

Polarizing angle, \theta_{P} = tan^{- 1}{2.2} = 65.56^{\circ}

Given:

Critical angle, \theta_{cr} = 27^{\circ}

Solution:

Now, in Total Internal Reflection (TIR), the critical angle for cubic zirconia is given by:

sin\theta_{cr} = \frac{1}{\mu_{Z}}                      (1)

where

{\mu_{Z} = refractive index of zirconia

From eqn (1):

\mu_{Z} = \frac{1}{sin\theta_{cr}}

\mu_{Z} = \frac{1}{sin(27^{\circ})} = 2.2

Now, the angle of polarization is given by:

tan\theta_{P} = \mu_{Z}

Therefore,

\theta_{P} = tan^{- 1}{2.2} = 65.56^{\circ}

8 0
3 years ago
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