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Aleks04 [339]
3 years ago
10

A metal wire is bent into a square and carries auniform current throughout it. The net magneticfield at the center of this squar

e is zero.•The net magnetic field inside a conductor mustbe zero.
a. True
b. False
Physics
1 answer:
belka [17]3 years ago
3 0

Answer:

The statement that the net magnetic field at the center of this square is zero is false.

The net magnetic field inside a conductor must be zero - This is a true statement

Explanation:

The net magnetic field at the center of this square is not equal to  zero.

The net magnetic field at the center of this square is given by the equation below:

B = 2√2μ₀I/πₐ

Where a = the side of the loop, and I is the current.

Thus, the statement that the net magnetic field at the center of this square is zero is false.

The net magnetic field inside a conductor must be zero - This is a true statement because the total charge on the conductor must be equal to zero.

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Answer:

Option B is correct.

A double insulated drill generally has a plastic case with the electrical connections and motor insulated within the tool

Explanation:

A double insulated drill's design in real life has plastic casing as the insulator & it wouldn't be a drill without its motor now, would it!?

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3 years ago
If a stereo has a dial that changes the volume of sounds the stereo makes what is the dial doing
vredina [299]
The volume dial is acting as a voltage divider or a variable resistor. 
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3 years ago
Read 2 more answers
According to Coulomb’s Law, what happens to the force when the distance increase between 2 particles?
ohaa [14]

Answer:

The size of the force varies inversely as the square of the distance between the two charges. Therefore, if the distance between the two charges is doubled, <u>the attraction or repulsion becomes weaker</u>, decreasing to one-fourth of the original value.

Explanation:

Coulomb’s law, mathematical description of the electric force between charged objects. Formulated by the 18th-century French physicist Charles-Augustin de Coulomb, it is analogous to Isaac Newton’s law of gravity.

Both gravitational and electric forces decrease with the square of the distance between the objects, and both forces act along a line between them. In Coulomb’s law, however, the magnitude and sign of the electric force are determined by the electric charge, rather than the mass, of an object. Thus, charge determines how electromagnetism influences the motion of charged objects. Charge is a basic property of matter. Every constituent of matter has an electric charge with a value that can be positive, negative, or zero.

Coulomb's Law says that the force between 2 charges is proportional to the product of the quantities of charge on each and inversely proportional to the square of the distance between them. The formula for Coulomb's Law is F=k\frac{q_{1}q_{2}   }{r^{2} }.

F is the force.

k is the Coulomb's constant (8.987*10^{9} \frac{Nm^{2} }{C^{2} }).

q_{1} is the electric charge of object 1.

q_{2} is the electric charge of object 2.

r is the distance between the two charges.

Electric force is inversely proportional to (r^{2}) instead of (r). As the distance between charges increases, the electric force decreases by a factor of \frac{1}{r^{2} }.

8 0
2 years ago
2. Two long parallel wires each carry a current of 5.0 A directed to the east. The two wires are separated by 8.0 cm. What is th
Gre4nikov [31]

Answer:

The magnitude of magnetic field at given point = 5.33 × 10^{-5} T

Explanation:

Given :

Current passing through both wires = 5.0 A

Separation between both wires = 8.0 cm

We have to find magnetic field at a point which is 5 cm from any of wires.

From biot savert law,

We know the magnetic field due to long parallel wires.

⇒ B = \frac{\mu_{0}i }{2\pi R}

Where B = magnetic field due to long wires, \mu_{0} = 4\pi \times10^{-7}, R = perpendicular distance from wire to given point

From any one wire R_{1}  = 5 cm, R_{2}  = 3 cm

so we write,

∴ B = B_{1} + B_{2}

 B = \frac{\mu_{0} i}{2\pi R_{1} } +  \frac{\mu_{0} i}{2\pi R_{2} }

 B =\frac{ 4\pi \times10^{-7} \times5}{2\pi } [\frac{1}{0.03} + \frac{1}{0.05} ]

 B = 5.33\times10^{-5}  T

Therefore, the magnitude of magnetic field at given point = 5.33\times10^{-5} T

3 0
3 years ago
Energy Calculation 4. What is the gravitational potential energy of an object that has a mass of 100kg it is 10m off of the grou
konstantin123 [22]
100kg * 9.8N/kg * 10m = 9800

3 0
2 years ago
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