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lesantik [10]
3 years ago
5

Sometimes, even with a wrench, one cannot loosen a nut that is frozen tightly to a bolt. It is often possible to loosen the nut

by slipping one end of a long pipe over the wrench handle and pushing at the other end of the pipe. With the aid of the pipe, does the applied force produce a smaller torque, a greater torque, or the same torque on the nut?
Physics
1 answer:
DIA [1.3K]3 years ago
8 0

Answer:

Explanation:

Torque is defined as the product of force and the perpendicular distance from the application of force.

It is a vector quantity.

Torque = force x perpendicular distance

To loosen a nut, if we increase the amount of distance, the torque is increased by applying a little amount of force and hence it is easy to open the nut.

Thus, it is easy to open a nut by slipping one end of a long pipe over the wrench handle and pushing at the other end of the pipe so that the torque is more and the nut is loosen.

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4 years ago
At each corner of a square of side l there are point charges of magnitude Q, 2Q, 3Q, and 4Q.What is the magnitude and direction
bogdanovich [222]

Answer:

magnitude of force on charge 2Q  = \frac{KQ^{2} }{I^{2} }

Direction of force on charge = 61 ⁰

Explanation:

The magnitude on the force on the charge can be evaluated by finding the net force acting on the charge 2Q  i.e x-component of the net force and the y-component of the net force

║F║ = \sqrt{f_{x}^{2} + f_{y}^{2}    }  =  after considering the forces coming from Q, 3Q and 4Q AND APPLYING COULOMBS LAW

magnitude of force acting on 2Q = \frac{KQ^{2} }{I^{2} }

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therefore ∅ = tan^{-1}  1.8284

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