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lesantik [10]
3 years ago
5

Sometimes, even with a wrench, one cannot loosen a nut that is frozen tightly to a bolt. It is often possible to loosen the nut

by slipping one end of a long pipe over the wrench handle and pushing at the other end of the pipe. With the aid of the pipe, does the applied force produce a smaller torque, a greater torque, or the same torque on the nut?
Physics
1 answer:
DIA [1.3K]3 years ago
8 0

Answer:

Explanation:

Torque is defined as the product of force and the perpendicular distance from the application of force.

It is a vector quantity.

Torque = force x perpendicular distance

To loosen a nut, if we increase the amount of distance, the torque is increased by applying a little amount of force and hence it is easy to open the nut.

Thus, it is easy to open a nut by slipping one end of a long pipe over the wrench handle and pushing at the other end of the pipe so that the torque is more and the nut is loosen.

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A 100-kg tackler moving at a speed of 2.6 m/s meets head-on (and holds on to) an 92-kg halfback moving at a speed of 5.0 m/s. Pa
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Given that,

Mass of trackler, m₁ = 100 kg

Speed of trackler, u₁ = 2.6 m/s

Mass of halfback, m₂ = 92 kg

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To find,

Mutual speed immediately after the collision.

Solution,

The momentum of the system remains conserved in this case. Let v is the mutual speed after the collision. Using conservation of momentum as :

m_1u_1+m_2u_2=(m_1+m_2)V\\\\V=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}\\\\V=\dfrac{100\times 2.6+92\times (-5)}{(100+92)}\\\\V=-1.04\ m/s

So, the mutual speed immediately after the collision is 1.04 m/s but in opposite direction.

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Explanation:

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