Answer:
Thus 100.00 g of sucrose contains 42.11 g of carbon, 6.48 g of hydrogen, and 51.41 g of oxygen; to two decimal places, the percent composition of sucrose is indeed 42.11% carbon, 6.48% hydrogen, and 51.41% oxygen.
Explanation:
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Answer:
The mol fraction of cyclohexane in the liquid phase is 0.368
Explanation:
Step 1: Data given
Mass of cyclohexane = 25.0 grams
Mass of 2-methylpentane = 44.0 grams
Temperature = 35.0 °C
The pressure of cyclohexane = 150 torr
The pressure of 2-methylpentane = 313 torr
The pressure we only need for the mole fraction in gas phase.
Step 2: Calculate moles of cyclohexane
Moles cyclohexane = mass cyclohexane / molar mass
Moles cyclohexane = 25.0 g / 84 g/mol = 0.298 mol of cyclohexane
Step 3: Calculate moles of 2-methylpentane
Moles = 44.0 grams / 86 g/mol = 0.512 mol of 2-methylpentane
Step 4: Calculate mole fraction of cyclohexane in the liquid phase
Mole fraction of C6H12:
0.298 / (0.298 + 0.512) = 0.368
The mol fraction of cyclohexane in the liquid phase is 0.368
Answer:A
Explanation: because i saw the sheet
The correct answer is D. Elements are created that differ from the reactants.. Because in a eeaction, the product is different than the reactants. Take NaCl for example.
Sodium, Atomic mass: 22.989769 g
You can see in a periodic table