<span>The best answer among
the choices is the first option. The chemical property of soda is that it is a
highly basic substance. It's chemical name is sodium carbonate. It is more
basic than sodium bicarbonate. Adding soda ash in a solution would increase the
pH of the solution.</span>
Answer:
A
Explanation:
First, we're given that the atmospheric pressure is 744.8 mmHg. However, this includes the pressure of the Zinc and the pressure of the water; we only want the pressure of the water, so subtract its pressures (23.8 mmHg) from 744.8 mmHg: 744.8 - 23.8 = 721 mmHg.
Now, we can use the ideal gas law: PV = nRT.
- the pressure P is 721 mmHg
- the volume V is 7.80 L
- the moles n of Zinc is what we want to find in order to calculate the mass
- the gas constant R is 62.36 L mmHg / (mol K)
- the temperature T is 25.0°C, or 25.0 + 273 = 298 K
Plug all these in:
PV = nRT
(721 mmHg) * (7.80 L) = n * (62.36) * (298 K)
n ≈ 0.303 mol Zn
We need to convert this to grams, so use the molar mass of Zinc, which is 65.38 g/mol:
Thus, the answer is A.
Hibernation is an animal's state of being inactive and metabolic depression. It is a season of heteronomy, which means that enter in a state of low body temperature, slow breathing, and heart rate. There are some species such as reptiles and snakes that hibernates in Arizona.
Answer:
The answer to your question is: letter B
Explanation:
First, write the reactions and balance them
a. 2 CH3OH + 3 O2 ⇒ 2 CO2 + 4 H2O
ratio 3/2 = 1.5
b. 2 CH2 = CHCH3 + 9 O2 ⇒ 3 CO2 + 3 H2O
ratio 9/2 = 4.5
c. 2 CH ≡ CH + 5 O2 ⇒ 4 CO2 + 2 H2O
ratio 5/2 = 2.5
Answer:
The answer to your question is molality = 0.34
Explanation:
Data
mass of NaBr = 14.57 g
mass of water = 415 g.
molality = ?
Process
1.- Calculate the molar mass of NaBr
NaBr = 23 + 80 = 103 g
2.- Calculate the moles of NaBr
103 g of NaBr ------------------ 1 mol
14.57 g of NaBr --------------- x
x = (14.57 x 1) / 103
x = 14.57 / 103
x = 0.141 moles
3.- Calculate the molality
molality = moles / volume
-Substitution
molality = 0.141 / .415
-Result
molality = 0.34