Answer:
1. a simulation 2. saurology
Explanation:
Answer:
0.570 L
Explanation:
Given:
Concentration of the HCl solution = 0.750 M
Mass of NaCl in the reaction = 25.0
Number of moles of NaCl in the reaction = Mass of NaCl / Molar mass of NaCl
also,
Molar mass of NaCl = 22.98 + 35.45 = 58.43 grams
thus,
Number of moles of NaCl in the reaction = 25 / 58.43 = 0.4278 moles
now,
1 mol of NaCl reacts to form 1 mol of HCl
thus,
0.4278 moles of NaCl reacts to form 0.4278 mol of HCl
also,
Concentration = Moles / volume of solution
0.750 = 0.4278 / volume of solution
or
volume of solution = 0.570 L
Answer: Concentration of at equilibrium = 0.08 M
Concentration of at equilibrium =0.08 M
Concentration of = 0.64M
Explanation:
Moles of = 4.00 mole
Volume of solution = 5.00 L
Initial concentration of =
Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as
For the given chemical reaction:
Initial conc. 0.8 M 0 M 0 M
At eqm. conc. (0.8-2x) M (x) M (x) M
The expression for is written as:
Concentration of at equilibrium = x M = 0.08 M
Concentration of at equilibrium = x M = 0.08 M
Concentration of = (0.8-2x) =
Answer:
The answer to your question is V2 = 3.7 L
Explanation:
Data
Volume 1 = 3.5 L
Temperature 1 = 25°C
Temperature 2 = 40°C
Pressure = cte.
Volume 2 = ?
Formula
To solve this problem use the Charles' law
V1/T1 = V2/T2
- Solve for V2
V2 = V1T2 / T1
- Convert temperature to °K
Temperature 1 = 25 + 273 = 298°K
Temperature 2 = 40 + 273 = 313°K
- Substitution
V2 = (3.5)(313) / 298
- Simplification
V2 = 1095.5 / 298
- Result
V2 = 3.7 L