Consider a neutron star of radius 10 km that spins with a period of 0.8 seconds. Imagine a person is standing at the equator of
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Resultant displacement is 29.2 km at north of west
Explanation:
To solve the problem, we have to use the rules of vector addition, resolving first each vector along the x- and y- direction.
Taking east as positive x direction and north as positive y- direction, we have:
- First displacement is 25.5 km east, therefore its components are
- Second displacement is 41.0 km northwest, so its components are
So, the components of the resultant displacement are
And so, the magnitude is calculated using Pythagorean's theorem:
And the direction is given by
Where the angle is measured from the west direction, since Rx is negative.
Learn more about displacement:
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