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pentagon [3]
3 years ago
12

Julian tests four springs and records the results in the table

Physics
2 answers:
Tju [1.3M]3 years ago
8 0

Answer:

list of spring in order of increasing spring constant is given by,

W, Y, X, Z

Explanation:

Spring W:

Magnitude of Force applied on the spring is given by,

F = k x

Where, F = force applied

k = spring constant

x displacement

k = F/x

k = 20 / 0.5

k = 40 N/m

Spring X:

Magnitude of Force applied on the spring is given by,

F = k x

Where, F = force applied

k = spring constant

x displacement

k = F/x

k = 60 / 0.3

k = 200 N/m

Spring Y:

Magnitude of Force applied on the spring is given by,

F = k x

Where, F = force applied

k = spring constant

x displacement

k = F/x

k = 40 / 0.4

k = 100 N/m

Spring Z:

Magnitude of Force applied on the spring is given by,

F = k x

Where, F = force applied

k = spring constant

x displacement

k = F/x

k = 50 / 0.1

k = 500 N/m

Thus, list of spring in order of increasing spring constant is given by,

W, Y, X, Z





Cerrena [4.2K]3 years ago
4 0

the correct answer is a. w,y,x,z.

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A 0.5 kg block of aluminum (caluminum=900J/kg⋅∘C) is heated to 200∘C. The block is then quickly placed in an insulated tub of co
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Answer: When 1.0kg of aluminium block is used, the final temperature of the mixture will be T = 36.2∘C

If 1.0kg copper block is used, T of the mixture will be = 17.4∘C

If 100g (0.1kg) of ice at 0∘C is used, T will be = 64.9∘C

If 25g (0.025Kg) of ice is used, T will be= 147.1∘C

Explanation:

H = mcΘ

heat lost by block = heat gained by water

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0.5*900*(200-20) = m₁*4186*(20-0)

m₁ = 450*180/83270

<em>m₁ = 0.973kg</em>

<em>when 1.0kg of aluminium block is used, the final temperature of the mixture will be </em><em>T</em>

heat lost by block = heat gained by water

1.0*900*(200-T) = 0.973*4186*(T-0)

180000 - 900T = 4073T

4973T = 180000

T = 180000/4973 = 36.2∘C

<em>If 1.0kg copper block is used, T of the mixture will be</em>

heat lost by block = heat gained by water

1.0*387*(200-T) = 0.973*4186*(T-0)

77400 - 387T = 4073T

4460T = 77400

T = 77400/4460 = 17.4∘C

<em>If 100g (0.1kg) of ice at 0∘C is used, T will be</em>

<em>heat lost by block = heat gained by water + heat used in melting ice to form water at 0∘C</em>

heat used in melting 0.1kg of ice, H = ml, where l= 33600J/Kg

0.5*900*(200-T) = 0.1*4186*(T-0) + 0.1*33600J/Kg

90000 - 450T =  418.6T + 33600

418.6T + 450T = 90000 - 33600

868.6T = 56400

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104.65T + 450T = 90000 - 8400

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