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3 years ago

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15. List the substances A-E in order from most dense to least dense based on the facts provided.

1 answer:

Volgvan3 years ago

3 0

Answer:

So 1st it is B then D then E then a then C

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Ethanol (C2H5OH) melts at –114 °C and boils at 78 °C. The enthalpy of fusion of ethanol is 5.02 kJ/mol, and its enthalpy of vapo

alexandr1967 [171]

Answer:

First question

$Q = 36826 \ J$

Second question

$Q = 52299.7 \ J$

Explanation:

From the question we are told that

The melting point of Ethanol is $T_m = -114 ^oC$

The boiling point of Ethanol is $T_b = 78^ oC$

The enthalpy of fusion of Ethanol is $F = 5.02 \ kJ / mol = 5.02 *10^{3}\ kJ / mol$

The enthalpy of vaporization of Ethanol is $L = 38.56 \ kJ / mol = 38.56 *10^{3} \ J / mol$

The specific heat of solid Ethanol is $c_e = 0.97 \ J/ g \cdot K$

The specific heat of liquid Ethanol is $c_l = 2.3 \ J / g \cdot K$

The mass of the Ethanol given is $m = 35.0 \ g$

Considering the first question

The initial temperature is $T_i = 27^oC$

The final temperature is $T_f = 120^oC$

Generally the heat required too raise the Ethanol to its boiling point is mathematically represented as

$Q_1 = m * c_l * (T_b - T_i)$

=> $Q_1 = 35.0 * 2.3 * ( 78 - 27)$

=> $Q_1 =4106 \ J$

Genially the number of moles of Ethanol given is mathematically represented as

$n = \frac{m}{Z}$

Here Z is the molar mass of Ethanol with value $Z = 46 g/mol$

So

$n = \frac{35}{46 }$

=> $n = 0.7609 \ mol$

Generally the heat of vaporization of the Ethanol is mathematically represented as

$Q_2 = n * L$

=> $Q_2 =0.7809 * 38.56 * 10^{3}$

=> $Q_2 =29339 \ J$

Generally the heat required too raise the Ethanol from its boiling point to $T_f$ is mathematically represented as

$Q_3 = m * c_l * (T_f - T_b)$

=> $Q_3 = 35 * 2.3 * (120 - 78 )$

=> $Q_3 = 3381 \ J$

Generally the total heat required is

$Q = Q_1 + Q_2 + Q_3$

=> $Q = 4106 + 29339 + 3381$

=> $Q = 36826 \ J$

Considering the second question

The initial temperature is $T_i = -120^oC$

The final temperature is $T_f = 120^oC$

Generally the heat required too raise the Ethanol to its melting point is mathematically represented as

$Q_1 = m * c_e * (T_m - T_i)$

=> $Q_1 = 35.0 * 0.97 * ( -114 - (- 120) )$

=> $Q_1 = 203.7 \ J$

Generally the heat of fusion of the Ethanol is mathematically represented as

$Q_2 = n * F$

=> $Q_2 =0.7809 * 5.02 *10^{3}$

=> $Q_2 =3920 \ J$

Generally the heat required too raise the Ethanol to its boiling point is mathematically represented as

$Q_3 = m * c_l * (T_b - T_m)$

=> $Q_3 = 35.0 * 2.3 * ( 78 - (- 114) )$

=> $Q_3 =15456 \ J$

Generally the heat of vaporization of the Ethanol is mathematically represented as

$Q_4 = n * L$

=> $Q_4 =0.7809 * 38.56 * 10^{3}$

=> $Q_4 =29339 \ J$

Generally the heat required too raise the Ethanol from its boiling point to $T_f$ is mathematically represented as

$Q_5 = m * c_l * (T_f - T_b)$

=> $Q_5 = 35 * 2.3 * (120 - 78 )$

=> $Q_5 = 3381 \ J$

Generally the total heat required is

$Q = Q_1 + Q_2 + Q_3+Q_4 + Q_5$

=> $Q = 203.7 + 3920 + 15456 +29339+3381$

=> $Q = 52299.7 \ J$

5 0

2 years ago

14. Why does a sea breeze blow from the ocean toward the shore?

shepuryov [24]

A. The breeze blow from higher pressure over the water to the lower

4 0

3 years ago

Can someone please help me with this?

Sergio039 [100]

Amu valie on the top and abundsnce percent in decimals on the bottom for each isotope

7 0

3 years ago

Determine how many liters of hydrogen adjusted to STP there are in a 50.0 liter steel cylinder if the pressure inside is 100.0 a

Dvinal [7]

Answer : The volume of hydrogen gas at STP is 4550 L.

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 100.0 atm

$P_2$ = final pressure of gas at STP = 1 atm

$V_1$ = initial volume of gas = 50.0 L

$V_2$ = final volume of gas at STP = ?

$T_1$ = initial temperature of gas = $27.0^oC=273+27.0=300K$

$T_2$ = final temperature of gas at STP = $0^oC=273+0=273K$

Now put all the given values in the above equation, we get:

$\frac{100.0atm\times 50.0L}{300K}=\frac{1atm\times V_2}{273K}$

$V_2=4550L$

Therefore, the volume of hydrogen gas at STP is 4550 L.

3 0

3 years ago

A substance that prevents the flow of electric current is a(n) .

nasty-shy [4]

An Insulator.

Insulators prevent flow of electric current. Example is wood, clay.

4 0

3 years ago

Read 2 more answers