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Nastasia [14]
3 years ago
10

Write the Henderson-Hasselbalch equation for a propanoic acid solution (CH3CH2CO2H, pKa = 4.874) using the symbols HA and A–, an

d the given pKa value for propanoic acid in the expression
Chemistry
1 answer:
Luden [163]3 years ago
7 0
The Henderson-Hasselbalch approximation is for conjugate acid-base pairs in a buffered solution. We're going to call HA a weak acid, and A- its conjugate base. The equation is as follows:
pH = pKa + log([base]/[acid]), where the brackets imply concentrations
Plugging in our symbols and the pKa value, the equation becomes:
pH = 4.874 + log([A-]/[HA])
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If a gas is 16 times as heavy as hydrogen which will diffuse faster and by what ratio​
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Answer:

1. Hydrogen will diffuse faster.

2. The ratio of diffusion of hydrogen gas to that of the unknown gas is 4 : 1

Explanation:

Let the rate of diffusion of hydrogen gas, H2 be R1

Let the molar mass of H2 be M1

Let the rate of diffusion of the unknown gas be R2.

Let the molar mass of the unknown gas be M2.

Molar mass of H2 (M1) = 2x1 =2g/mol

Molar mass of unknown gas (M2) = 16 times that of H2

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1. Determination of the gas that will diffuse faster. This is illustrated below:

R1/R2 = √(M2/M1)

R1/R2 = √(32/2)

R1/R2 = √16

R1/R2 = 4

Cross multiply

R1 = 4R2

From the above calculations, we can see that the rate of diffusion H2 (R1) is four times the rate of diffusion of the unknown gas (R2).

Therefore, hydrogen will diffuse faster.

2. Again, from the calculations made above, the ratio of diffusion of hydrogen (R1) to that of the unknown gas (R2) is given by;

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7 0
3 years ago
If the volame ofa gas coetainer at 32°C changes froem 1.55 L to 753 ml, what will the final temperature be? Assume the pressure
motikmotik

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T_1 = initial temperature of gas = 32^oC=273+32=305K

T_2 = final temperature of gas = ?

Now put all the given values in the above formula, we get the final temperature of the gas.

\frac{1.55L}{0.753L}=\frac{305K}{T_2}

T_2=149K

Therefore, the final temperature of gas will be, 149 K

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