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Nastasia [14]
3 years ago
10

Write the Henderson-Hasselbalch equation for a propanoic acid solution (CH3CH2CO2H, pKa = 4.874) using the symbols HA and A–, an

d the given pKa value for propanoic acid in the expression
Chemistry
1 answer:
Luden [163]3 years ago
7 0
The Henderson-Hasselbalch approximation is for conjugate acid-base pairs in a buffered solution. We're going to call HA a weak acid, and A- its conjugate base. The equation is as follows:
pH = pKa + log([base]/[acid]), where the brackets imply concentrations
Plugging in our symbols and the pKa value, the equation becomes:
pH = 4.874 + log([A-]/[HA])
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I do not understand this question if someone could help please
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\bold{\huge{\blue {\underline{ Answer}}}}

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Dipole-dipole interactions are typically stronger than <em>induced</em> dipole<em> </em>in isomers. As a result, the 1,2 isomer has a higher melting point.

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mr Goodwill [35]
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