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rosijanka [135]
3 years ago
6

new generation cordless phones use a 9.00x10^2 MHz frequency and can be operated up to 60.0 m from their base. how many waveleng

ths of the electromagnetic waves can fit between your ear and a base 60.0 m away?
Physics
1 answer:
Musya8 [376]3 years ago
3 0
Λ = 3*10^8 / 9*10^8 = 1/3 m
no. of wavelengths = 60/(1/3) = 180
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An astronaut landed on a far away planet that has a sea of water. To determine the gravitational acceleration on the planet's su
sergiy2304 [10]

To solve this problem it is necessary to apply the concepts related to hydrostatic pressure or pressure due to a fluid.

Mathematically this pressure is given under the formula

P_h = \rho g h

Where,

\rho = Density

h = Height

g = Gravitational acceleration

Rearranging in terms of g

g = \frac{P_h}{\rho h}

our values are given as

P_h = 1.1 atm (\frac{101325Pa}{1atm}) = 111457.5Pa

\rho = 1000kg/m^3

h = 12.3m

Replacing we have

g = \frac{111457.5}{(1000)(12.3)}

g = 9.061m/s^2

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3 years ago
What equation is used to calculate the weight of an object on a plant ?
tankabanditka [31]

The equation used to calculate the weight of an object on a plant is F = ma. "F" is the force measures  in Newtons, "m" is the mass measures in grams and "a" is the acceleration that accur  due to gravity.

3 0
4 years ago
The reaction mixture represented above is at equilibrium at 298 K. The value of the equilibrium constant for the reaction is 16
andre [41]

Answer : The equilibrium concentration of T(g) is 0.5 M

Solution :

Let us assume that the equilibrium reaction be:

The given equilibrium reaction is,

R(g)+2T(g)\rightleftharpoons 2X(g)+Z(g)

The expression of K_c will be,

K_c=\frac{[Z][X]^2}{[R][T]^2}

where,

K_c = equilibrium constant = 16

[Z] = concentration of Z at equilibrium = 2.0 M

[R] = concentration of R at equilibrium = 2.0 M

[X] = concentration of X at equilibrium = 2.0 M

[T] = concentration of T at equilibrium = ?

Now put all the given values in the above expression, we get:

16=\frac{(2.0)\times (2.0)^2}{(2.0)\times [T]^2}

[T]=0.5M

Therefore, the equilibrium concentration of T(g) is 0.5 M

8 0
4 years ago
A bicyclist rides 2.93 km due east, while the resistive force from the air has a magnitude of 8.65 N and points due west. The ri
Ilya [14]

Answer:

-50.6 kJ

Explanation:

The work done (W) on an object is given by:

W = (Fcosθ) * S

where F is the force, S is the displacement and θ is the angle between the force and displacement.

i) During the first trip riding east, S₁ = 2.93 km = 2930 m, F₁ = 8.65 N.

The displacement is due east and the force is due west, hence θ₁ = 180°. Therefore:

W₁ = (F₁ * cosθ₁)S₁ = (8,65 * cos(180))2930 = -25.3 kJ

ii) i) During the second trip riding west, S₂ = 2.93 km = 2930 m, F₂ = 8.65 N.

The displacement is due west and the force is due east, hence θ₂ = 180°. Therefore:

W₂ = (F₂ * cosθ₂)S₂ = (8,65 * cos(180))2930 = -25.3 kJ

work done by the resistive force during the round trip is:

W = W₁ + W₂ = -25.3 kJ + (-25.3 kJ) = -50.6 kJ

4 0
3 years ago
Reading accuracy of stop watch
Mice21 [21]

Answer:

Is there a more speciific question?

Explanation:

3 0
3 years ago
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