You can separate out the canola oil easily, because it has cooled down enough to turn back into a solid.
Answer:
(1) Cl₂ is the limiting reactant.
(2) 8.18 g
Explanation:
- 2Na(s) + Cl₂(g) → 2NaCl(s)
First we <u>convert the given masses of reactants into moles</u>, using their <em>respective molar masses</em>:
- Na ⇒ 12.0 g ÷ 23 g/mol = 0.522 mol Na
- Cl₂ ⇒ 5.00 g ÷ 70.9 g/mol = 0.070 mol Cl₂
0.070 moles of Cl₂ would react completely with (2 * 0.070) 0.14 moles of Na. There are more Na moles than that, so Na is the reactant in excess while Cl₂ is the limiting reactant.
Then we <u>calculate how many moles of NaCl are formed</u>, <em>using the limiting reactant</em>:
- 0.070 mol Cl₂ *
= 0.14 mol NaCl
Finally we <u>convert NaCl moles into grams</u>:
- 0.14 mol NaCl * 58.44 g/mol = 8.18 g
When dT = Kf * molality * i
= Kf*m*i
and when molality = (no of moles of solute) / Kg of solvent
= 2.5g /250g x 1 mol /85 g x1000g/kg
=0.1176 molal
and Kf for water = - 1.86 and dT = -0.255
by substitution
0.255 = 1.86* 0.1176 * i
∴ i = 1.166
when the degree of dissociation formula is: when n=2 and i = 1.166
a= i-1/n-1 = (1.166-1)/(2-1) = 0.359 by substitution by a and c(molality) in K formula
∴K = Ca^2/(1-a)
= (0.1176 * 0.359)^2 / (1-0.359)
= 2.8x10^-3
find mol of N2 present using gas law equation
PV = nRT
P = pressure = 688/760 = 0.905 atm.
V = 100mL = 0.1L
n = ???
R = 0.082057
T = 565+273 = 838
Substitute:
0.905*0.1 = n*0.082057*838
n = 0.0905 / 68.76
n = 0.00132 mol N2
Molar mass N2 = 28 g/mol
0.00132 mol = 0.00132*28 = 0.037g N2 gas
When that happens, you get a plasma — the fourth state of matter.
