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3 years ago

Which statement is true according to Newton's second law of motion?

Physics

2 answers:

brilliants [131]3 years ago

7 0

According to Newton's second law we have:

F = ma

Where,

F: Sum of forces or net force applied

m: total mass of the object

a: acceleration of the object

We observe that the force and the acceleration are proportional, being the constant of proportionality the mass of the object.

Therefore, the object accelerates in the same direction as the applied force.

Answer:

An object accelerates in the same direction as that of the force applied.

Zarrin [17]3 years ago

6 0

The correct answer to the question is C).An object accelerates in the same direction as that of the force applied.

EXPLANATION:

Before going to answer this question, first we have to understand Newton's second laws of motion.

As per Newton's second laws of motion, the rate of change of momentum is directly proportional to the net external force and takes place along the direction of force.

Mathematically $F =\ \frac{dP}{dt}$

Here, P is the momentum and P = mv.

⇒ F = $\frac{d}{dt}(mv)$

= $m\frac{d}{dt}(v)$ [m = constant]

= ma.

Here, m and v are the mass and velocity of a body .

'a' stands for the acceleration of a body which is the rate of change of velocity.

In vector form it can be written as $\vec F=\ m\times\vec a$ .

Hence, it is obvious that the net external force is the product of mass with acceleration.

As mass is a scalar quantity, so we can say that force is simply the scalar multiple of mass with acceleration.

Hence, the direction of acceleration will be along the direction of force.

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A cylindrical capacitor has an inner conductor of radius 2.7 mmmm and an outer conductor of radius 3.1 mmmm. The two conductors

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Answer:

(A) Capacitance per unit length = $4.02 \times 10^{-10}$

(B) The magnitude of charge on both conductor is $Q = 4.22 \times 10^{-19}$ C and the sign of charge on inner conductor is $+Q$ and the sign on outer conductor is $-Q$

Explanation:

Given :

Radius of inner part of conductor $(R_{1})$ = $2.7 \times 10^{-3}$ m

Radius of outer part of conductor $(R_{2})$ = $3.1 \times 10^{-3}$ m

The length of the capacitor $(l)$ = $3 \times 10^{-3}$ m

(A)

Capacitance is purely geometrical property. It depends only on length, radius of conductor.

From the formula of cylindrical capacitor,

$C = \frac{2\pi\epsilon_{o} l }{ln\frac{R_{2} }{R_{1} } }$

Where, $\epsilon_{o} = 8.85 \times 10^{-12}$

But we need capacitance per unit length so,

$\frac{C}{l} = \frac{2\pi\epsilon_{o} }{ln\frac{R_{2} }{R_{1} } }$

capacitance per unit length = $\frac{6.28 \times 8.85 \times 10^{-12} }{ln(1.148)} = 4.02 \times 10^{-10}$

(B)

The charge on both conductors is given by,

$Q = C \Delta V$

Where, C = capacitance of cylindrical capacitor and value of $C = 12.06 \times 10^{-13}$ F, $\Delta V = 350 \times 10^{-3}$ V

∴ $Q = 4.22 \times 10^{-19}$ C

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Charge on inner conductor is $+Q$ and Charge on outer conductor is $-Q$ .

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Answer:

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Explanation:

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where,

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L = Distance between screen and slits

d = Slit Separation

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λ = 425 nm = 4.25 x 10⁻⁷ m

y = 2Δx = 0.0177 m => Δx = 8.85 x 10⁻³ m

Therefore,

8.85 x 10⁻³ m = (4.25 x 10⁻⁷ m)L/d

L/d = (8.85 x 10⁻³ m)/(4.25 x 10⁻⁷ m)

L/d = 2.08 x 10⁴

using this for λ = 560 nm = 5.6 x 10⁻⁷ m:

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